PROBLEM 21 - 0535: Develop a flow-chart for evaluating | the Fourier coefficients of the periodic waveform f(t) in the given figure. The values measured for f(t) are f(0) = 0, f(0.05) = 0.25, f(0.1) =...


PROBLEM 21 - 0535:<br>Develop a flow-chart for evaluating<br>|<br>the Fourier coefficients of<br>the periodic waveform f(t) in the<br>given figure. The values<br>measured for f(t) are f(0) = 0,<br>f(0.05) = 0.25, f(0.1) = 0.3,<br>%3D<br>f(0.15) = 0.5, f(0.2) = f(0.25) =<br>%3D<br>%3D<br>%3D<br>f(0.3) = 1.0, f(0.35) = 0.55,<br>f(0.4) = 0.3, f(0.45) = 0, f(0.5) =<br>%3D<br>-0.25, f(0.55) = f(0.6) = -0.3,<br>f(0.65) = -0.2, f(0.7) = -0.1, f(0.75)<br>= f(0.8) = f(0.85) = f(0.9)<br>%3D<br>%3D<br>= f(0.95) = 0.<br>%3D<br>

Extracted text: PROBLEM 21 - 0535: Develop a flow-chart for evaluating | the Fourier coefficients of the periodic waveform f(t) in the given figure. The values measured for f(t) are f(0) = 0, f(0.05) = 0.25, f(0.1) = 0.3, %3D f(0.15) = 0.5, f(0.2) = f(0.25) = %3D %3D %3D f(0.3) = 1.0, f(0.35) = 0.55, f(0.4) = 0.3, f(0.45) = 0, f(0.5) = %3D -0.25, f(0.55) = f(0.6) = -0.3, f(0.65) = -0.2, f(0.7) = -0.1, f(0.75) = f(0.8) = f(0.85) = f(0.9) %3D %3D = f(0.95) = 0. %3D

Jun 09, 2022
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