Pretend the results below were obtained for water from your well. The 10 mL tubes are Full Strength, or 9.9 mL of the sample plus 0.1 mL of 10x broth (here a fluorescent Brilliant Green Broth). The 1...


Pretend the results below were obtained for water from your well. The 10 mL tubes are Full Strength, or 9.9 mL of the sample plus 0.1 mL of 10x broth (here a fluorescent Brilliant Green Broth). The 1 mL tubes are 1 mL sample plus 9 mL of normal broth (so a ten-fold dilution). The 0.1 mL are that much sample with 9.9 mL of the broth (so a hundred-fold dilution).
Dark green indicates coliform presence.  Use the table and the figure and give me the MPN.


To do so,
count the number of positive tubes at each dilution.  Then match the counts to the set of values that most closely fits.  Yes, you need to consider the set of values for None, 1 and 0.1 taken together. For example, 5,2,1.


What is the MPN estimate for this well water sample?


If safe drinking water is <5 cells/100="" ml="" would="" you="" drink="" this="" well="">


10 ml<br>50 ml<br>1 ml<br>0.1 ml<br>

Extracted text: 10 ml 50 ml 1 ml 0.1 ml
Dilution<br># Tubes +<br>MPN<br>None = 10mL<br><5/100 ml<br>1/10 = 1 ml<br>0-1<br>1/100 = .1ml<br>%3D<br>None<br>1-2<br>10-20<br>1/10<br>1-2<br>1/100<br>None<br>100-200<br>1/10<br>1-2<br>1/100<br>None<br>2-3<br>500<br>1/10<br>1/100<br>None<br>4-5<br>1000<br>1/10<br>2<br>1/100<br>N O<br>N O<br>

Extracted text: Dilution # Tubes + MPN None = 10mL <5 100="" ml="" 1/10="1" ml="" 0-1="" 1/100=".1ml" %3d="" none="" 1-2="" 10-20="" 1/10="" 1-2="" 1/100="" none="" 100-200="" 1/10="" 1-2="" 1/100="" none="" 2-3="" 500="" 1/10="" 1/100="" none="" 4-5="" 1000="" 1/10="" 2="" 1/100="" n="" o="" n="">

Jun 11, 2022
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