I attached a formula sheet of the only formulas that can be used to solve problems. Will leave a vote!
Extracted text: Position, Velocity, Acceleration Rectangular Coordinate: i = xỉ + yj + zk ü = v,i + v,j + v,k = xi + ÿj + żk a = a,i + a,j + a,k = xï + ÿj+ žk Projectile Motion a = -gj v = vĩ + v,j = voxī+(-gt + voy)j Kinematic Equations for Two Points on the Same Rigid Body: %3D /A Pure Rolling: vc = rw; ac = ra, consistent with the rolling direction; v¡ = 0; a¡ = rw² toward C 7 = xĩ + yỹ = (Voxt + xo)ï + (–gt2 + voyt + Yo)j Eq. of Motion for a Rigid Body in Planar Motion: 1 gt² ΣF - Tangent and Normal Coordinate: * = 7(s) i = vũ; = sū; à = a,ū, + a„īn = šū, +ūn = māg ΣΜ 1ς α ΣΜΟ-10α EMQ = Iga + (Fc/ × mãc), = lọa + (Tc/Q × māo), Q: any point G: mass center O: pivot point or instantaneous center 213/2 1+] |d²y| p = Kinetic Energy of a Rigid Body dx2 T =mv,² +Igw² 2 Cylindrical Coordinate: = rū, + zū, v = v,ũ, + vgũg + v,ū, = rū, + rôūo + żū, à = a,ūr + agūg + azūz = (* – rô?)ũ, + (rö + 2řė)ūg + žū, T = Work Done on a Rigid Body - [ Fds + f Mdo U = Newton's Second Law: 2F = mã Work-Energy Principle: T; +U.-2 = T2 1 kinetic energy: T = mv² work done: U = F• dr *work of the force exerted by a spring: U1-2 = k(sỉ – s3) *work of the force exerted by friction: U1-2 = -fd Conservative Force Field: T1 + Vị = T2 + V2 T: kinetic energy V:potential energy
Extracted text: The crank arm AB tums about z axis thrdugh its pinned end A with the clockwise angular velocity w = 3 rad/s and counterclockwise angular acceleration a = 2 rad/s² at the instant shown. The block C slides in the vertical track. At the given instant, determine (a) position vector, îa/a, and velocity and acceleration at point B, vg and äg, (b) position vector, ře/B, velocity at point C, vc, and angular velocity of the link BC, ögc, and (c) acceleration at point C, år, and angular acceleration of the link BC, đgc. B 30° *50 3 m o- 3 rad's a-2 zad v A (7] (a) řbya = (10] (b) ře/u = [8] (c) âc =