Title of Report : AERO2562 - Assignment XXXXXXXXXX) Author: Microsoft Office User Save Date: 2020 Page 1 of 5 School of Engineering AERO2562 - Assignment 2- Aircraft Performance Total Marks: 165 2020...

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Answered Same DayApr 30, 2021AERO2562

Answer To: Title of Report : AERO2562 - Assignment XXXXXXXXXX) Author: Microsoft Office User Save Date: 2020...

Anju Lata answered on May 10 2021
164 Votes
Assignment
    S.no
    section
    Answer
    marks
    1
    a
    Given data
Weight =38,220 N
Wing area = 27.3 m2
Aspect ratio =7.5
Oswald efficiency factor (e)= 0.9
Zero-lift drag coefficient CD,0 = 0.03
Velocity =725 km/hr= 201.39 m/s
Density =1.225 kg/
m3

Steady and level flight Lift=Weight , Thrust = Drag
CL = 0.056
CD = CD0 +KCL2 K = 1/(π. e. A.R)
= .03 + 1.498 x 10-4
= 0.03015
Thrust = Drag x W/L
= CD x W/ CL
= 20.577 KN
    
    1
    b
    Given data
Weight =38,220 N
Wing area = 27.3 m2
Aspect ratio =7.5
Oswald efficiency factor (e)= 0.9
Zero-lift drag coefficient CD,0 = 0.03
Velocity = 675 km/hr= 187.5 m/s
Density = 0.777 kg/m3

Steady and level flight Lift=Weight , Thrust = Drag

CL = 0.1025
CD = CD0 +KCL2 K = 1/(π. e. A.R)
= .03 + 1.498 x 10-4
= 0.0305
Thrust = Drag x W/L
= CD x W/ CL
= 11.371 KN
    
    1
    c
    
Maximum velocity inversely proportional to density.5
As the density decreases with altitude v max will increase. it happen due to drag will decrease much larger as compared to thrust .It will happen till tropopause afterward it decreases. After tropopause thrust fall more quickly than drag.
At equator tropopause occurs at 50000 feet.
Relation between altitude and maximum velocity of jet engine
    
    2
    
    Given data
Weight = 5,000 lb, The wing area = 200 ft2 and aspect ratio= 8.5
The Oswald efficiency factor (e) = 0.93
ρ∞ = 0.002377 slug/ft3
Velocity = 700 Km/hr = 700x 0.911344 =637.94 ft/s

Steady and level flight Lift=Weight , Thrust = Drag

CL = 0.05169
Maximum L/D condition
CD0 = K CL2
CD0 =KCL2 = 1.0757x 10-4 K = 1/(π. e. A.R)
CD = 2.151 x 10-4
Thrust = Drag x W/L
= CD x W/ CL
= 20.811lb
    
    3
    a
    Given data
Wing area = 47 m2
Aspect ratio = 6.5
Oswald
Efficiency factor = 0.87
Weight = 103,047 N
Zero-lift drag coefficient = 0.032
Velocity = 160m/s
Thrust = 40298 x2= 80596 N
Power require = Drag x Velocity

CL =0.14
CD = CD0 +KCL2 K = 1/(π. e. A.R)
= .033
D = .5x v2 CD
= 24407 N
Power required = 24407.71 x 160
=3904.8 KW
    
    3
    b
    Wing area = 47 m2
Aspect ratio = 6.5
Oswald
Efficiency factor = 0.87
Weight = 103,047 N
Zero-lift drag coefficient = 0.032
Thrust = 40298 x2= 80596 N
Maximum velocity will occur when power required is equal to power available
VMax can be directly found by formula
T/ w =.782
w/s = 2192.49
K = 1/(π. e. A.R )=0.056
Substituting above values in v...
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