Please I need to solve the 4il, J Matrix method J H.W ----2 -- Example 3.3 For the circuit shown in Fig. 3.9, find the node voltages Solution: The supemode contains the 2-V source, nodes I and 2, and...


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Please I need to solve the<br>4il, J Matrix method J<br>H.W<br>----2<br>--<br>Example 3.3<br>For the circuit shown in Fig. 3.9, find the node voltages<br>Solution:<br>The supemode contains the 2-V source, nodes I and 2, and the 10-11<br>resistor. Applying KCL. to the supernode as shown in Fig. 3.10(a) gives<br>2V<br>2=i, +i +7<br>2A O 2a 40 1A Expressing í, and iz in terms of the node voltages<br>2.<br>- S-20, + + 28<br>Figure 3.9<br>For Example 33<br>-20 - 20,<br>(33.1)<br>To get the relationship between v, and ey, we apply KVL to the circuit<br>in Fig. 3.10(b). Going around the loop, we obtain<br>-, - 2+ e =0 =e, +2 a32)<br>From Eqs. (13.1) and (33.2), we write<br>u = , +2=-20 - 20,<br>

Extracted text: Please I need to solve the 4il, J Matrix method J H.W ----2 -- Example 3.3 For the circuit shown in Fig. 3.9, find the node voltages Solution: The supemode contains the 2-V source, nodes I and 2, and the 10-11 resistor. Applying KCL. to the supernode as shown in Fig. 3.10(a) gives 2V 2=i, +i +7 2A O 2a 40 1A Expressing í, and iz in terms of the node voltages 2. - S-20, + + 28 Figure 3.9 For Example 33 -20 - 20, (33.1) To get the relationship between v, and ey, we apply KVL to the circuit in Fig. 3.10(b). Going around the loop, we obtain -, - 2+ e =0 =e, +2 a32) From Eqs. (13.1) and (33.2), we write u = , +2=-20 - 20,

Jun 11, 2022
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