Problems 1 - 2 A sample of 150 college students at a large university reports getting an average of 6.55 hours of sleep last night with a standard deviation of 1.82 hours. 1.Use a t distribution to...

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Problems 1 - 2 A sample of 150 college students at a large university reports getting an average of 6.55 hours of sleep last night with a standard deviation of 1.82 hours. 1.Use a t distribution to construct a 98% confidence interval for the average amount of sleep students at this university got last night. Use two decimal places in your margin of error. Use Stat Tests T Interval. A) 4.73 to 8.97 hours B) 6.14 to 7.96 hours C) 5.32 to 8.14 hours D) 6.20 to 6.90 hours 2.Suppose you want to conduct a similar study at your university. Assuming that the standard deviation of this sample is a reasonable estimate of the standard deviation of sleep time at your university, how many students do you need to survey to estimate the mean sleep time of students at your university with 95% confidence and a margin of error of 0.8 hours? Use Z = 1.96. A) 18 students B) 23 students C) 20 students D) 15 students Problems 3 – 5: November 6, 2012 was election day. Many of the major television networks aired coverage of the incoming election results during the primetime hours. The provided boxplot displays the amount of time (in minutes) spent watching election coverage for a random sample of 20 U.S. adults. In this sample, the average time spent watching election coverage was 81.44 minutes with standard deviation of 42.33 minutes. 3.Is it reasonable to use the t-distribution to construct a confidence interval for the average amount of time spent watching election coverage by U.S. adults? True or False. 4.Construct a 90% confidence interval for the average amount of time U.S. adults spent watching election coverage. Use two decimal places in your margin of error. Use Stat Tests T Interval A) 61.26 to 91.35 minutes B) 65.08 to 97.81 minutes C) 54.23 to 89.65 minutes D) 65.39 to 96.49 minutes 5.What sample size would we need to estimate the average amount of time U.S. adults watching election coverage with 99% confidence and a margin of error of 7 minutes? Use z = 2.575. A) 321 U.S. Adults B) 108 U.S. Adults C) 157 U.S. Adults D) 243 U.S. Adults 6. Consider taking random samples of size 50 from Population A with proportion 0.88 and random samples of size 70 from Population B with proportion 0.81. Find the mean of the distribution of differences in sample proportions, . A) - .07 B) .07 C) 1.07 D) .87 7. A random sample of 48 students at a large university reported getting an average of 6.5 hours of sleep on weeknights, with standard deviation 1.58 hours. A dotplot of the data is provided. It is recommended, for most college age students, to get 8 hours of sleep each night. Does this sample provide evidence, at the 5% level, that college students at this university get significantly less sleep, on average, than what is recommended? Use T Test. Answer True or False. Use the following to answer question 8: On November 15 - 18, 2012 Gallup conducted a survey of 1,015 randomly selected U.S.adults about "Black Friday" shopping. They asked the following question: "As you know, the Friday after Thanksgiving is one of the biggest shopping days of the year. Looking ahead, do you personally plan on shopping on the Friday after Thanksgiving, or not?" Of the 515 men who responded, 88 (17%) said "Yes." Of the 500 women who responded, 130 (26%) said "Yes." 8. Construct a 95% confidence interval for the difference between the proportion of men and women who planned to shop on the Friday after Thanksgiving. Use three decimal places when computing the margin of error. Use 2 Prop Z Interval. A) - .30714 to -.25014 B) ,3915 to .4127 C) -.14027 to - .03973 D) .14027 to .03973 Use the following to answer question 9: Observed counts from a sample are provided in the following table. The expected counts from a null hypothesis are given in parentheses. Category A B C Observed (Expected) 45 (52.33) 61 (52.33) 51 (52.33) 9.What is the - test statistic? A) 2.497 B) 3.711 C) 1.338 D) 7.503 2 c ± ˆˆ AB pp -
Answered Same DayDec 09, 2021

Answer To: Problems 1 - 2 A sample of 150 college students at a large university reports getting an average of...

Rajeswari answered on Dec 09 2021
147 Votes
Problems 1 - 2
A sample of 150 college students at a large university reports getting an average of 6.55 hours of sleep last night with a standard deviation o
f 1.82 hours.
    1.    Use a t distribution to construct a 98% confidence interval for the average amount of sleep students at this university got last night. Use two decimal places in your margin of error. Use Stat Tests T Interval.
    
        A) 4.73 to 8.97 hours
        B) 6.14 to 7.96 hours
        C) 5.32 to 8.14 hours
        D) 6.20 to 6.90 hours
    
Confidence interval = Mean ±t crit *se = 6.55±2.351635*(1.82)/sqrt 150 = (6.20, 6.90)
Option D
    2.    Suppose you want to conduct a similar study at your university. Assuming that the standard deviation of this sample is a reasonable estimate of the standard deviation of sleep time at your university, how many students do you need to survey to estimate the mean sleep time of students at your university with 95% confidence and a margin of error of 0.8 hours? Use Z = 1.96.
         A) 18 students
         B) 23 students
C) 20 students
          D) 15 students
                                            
Margin of error = 0.8=1.96*1.82/(sqrt n)    
So n >20
Option C
Problems 3 – 5:
November 6, 2012 was election day. Many of the major television networks aired coverage of the incoming election results during the primetime hours. The provided boxplot displays the amount of time (in minutes) spent watching election coverage for a random sample of 20 U.S. adults. In this sample, the average time spent watching election coverage was 81.44 minutes with standard deviation of 42.33...
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