ECO 578 SPRING 201 XXXXXXXXXXPage 1 of 18 Exam II  Work Problems from page(1 to 18): **All formula and work must be shown step by step and graphs need to be drawn.** ** Answers needs to be written in...

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Answer To: ECO 578 SPRING 201 XXXXXXXXXXPage 1 of 18 Exam II  Work Problems from page(1 to 18): **All formula...

Pritam answered on Apr 02 2021
145 Votes
1a) 30/200 = 0.15
1b) 15/200 = 0.075
1c) (10+10)/30 = 20/30 = 0.6667
1d) (15+15)/70 = 30/70 = 0.42
86
1e) (25+15)/(100+70) = 40/170 = 0.2353
1f) 10/30 = 0.3333
1g) YES, because Pr(A1 ∩ B1) = 25/200 = 1/8 = (50/200)*(100/200) = Pr(A1)*Pr(B1)
2a) 0.13857
2b) 0.99363
2c) 0.77713
2d) 0.00046
3a) 0.189
3b) 0.4718
4a) 20*0.6 = 12
4b) 20*0.6*(1-0.6) = 20*0.6*0.4 = 4.8
4c) 0.00027
4d) 0.006466
4e) 0.99839
5a) < 0.000001
5b) 0.0076733 - 0.0000028 = 0.0076705
6a) 6
6b) 20
6c) 21
6d) 15
7) E(X) = 1 * 0.326 + 2 * 0.214 + 3 * 0.115 + 4 * 0.304 + 5 * 0.041
= 0.326 + 0.428 + 0.345 + 1.216 + 0.205
= 2.520

E(X^2) = 1 * 0.326 + 4 * 0.214 + 9 * 0.115 + 16 * 0.304 + 25 * 0.041
= 8.106

Var(X) = E(X^2) - (E(X))^2
= 8.106 - 2.520^2
= 1.76

SD(X) = (Var(X))^0.5 = (1.76)^0.5 = 1.32665
8) A continuous random variable can take any value between two specified values, whereas a discrete random variable can only take...
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