please help solve attached below are questions pertaining to attached find the test statisitc find the p value State the conclusion for the test. A. Reject the null hypothesis. There is not sufficient...


please help solve attached below are questions pertaining to attached



find the test statisitc


find the p value


State the conclusion for the test.






A.Reject

the null hypothesis. There

is not

sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.





B.
Fail to reject
the null hypothesis. There
is not
sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.





C.
Reject
the null hypothesis. There
is
sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.





D.
Fail to reject
the null hypothesis. There
is
sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.



i<br>More Info<br>City #1<br>103<br>City #2<br>117<br>86<br>50<br>121<br>100<br>113<br>85<br>101<br>87<br>104<br>107<br>213<br>110<br>135<br>111<br>290<br>143<br>100<br>133<br>267<br>101<br>145<br>209<br>Print<br>Done<br>

Extracted text: i More Info City #1 103 City #2 117 86 50 121 100 113 85 101 87 104 107 213 110 135 111 290 143 100 133 267 101 145 209 Print Done
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of<br>baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected<br>from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level<br>to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.<br>Click the icon to view the data table of strontium-90 amounts.<br>What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2<br>consists of amounts from city #2.<br>O A. Ho: H1 #H2<br>H1:41> H2<br>B. Ho: H1 SH2<br>H1: H1 > H2<br>C. Ho: H1 = H2<br>H1: H1> H2<br>D. Ho: H1 = H2<br>H1: Hy # H2<br>The test statistic is<br>(Round to two decimal places as needed.)<br>

Extracted text: Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 #H2 H1:41> H2 B. Ho: H1 SH2 H1: H1 > H2 C. Ho: H1 = H2 H1: H1> H2 D. Ho: H1 = H2 H1: Hy # H2 The test statistic is (Round to two decimal places as needed.)
Jun 07, 2022
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