Physical Chemistry: Show complete solution.
Calculate the standard enthalpy change delta Ho, for the formation of 1 mole POCl3.
PCl5(g) + H2O(g) → POCl3(g ) + 2HCl(g)
The information available is"2P(white) + 3Cl2(g) + O2(g) → 2POCl3(g) - delta Ho= -1117 kJ
2HCl(g) → H2(g) + Cl2(g) - delta Ho= 184.6 kJ
3P(white) + 15/2 Cl2(g ) → 3PCl5(g) - delta Ho= -1124.7 kJ
2H2O(g ) → 2H2(g) + O2(g) - delta Ho= 483.6 kJ
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