Peter and Paul agree to meet at a restaurant at noon. Peter arrives at a time normally distributed with mean 12:00 noon, and standard deviations 5 minutes. Paul arrives at a time normally distributed...

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Peter and Paul agree to meet at a restaurant at noon. Peter arrives at a time normally distributed with mean 12:00 noon, and standard deviations 5 minutes. Paul arrives at a time normally distributed with mean 12:02 P.M. and standard deviation 3 minutes Assuming the Two arrival times are independent, find the chance that


a)      Peter arrives before Paul:           b) both mean arrive within 3 minutes of noon:


b)     The two men arrive within 3 minutes of each other.



Answered Same DayDec 26, 2021

Answer To: Peter and Paul agree to meet at a restaurant at noon. Peter arrives at a time normally distributed...

David answered on Dec 26 2021
120 Votes
(a) Let X and Y represent times when Peter and Paul arrive, respectively. We can take noon to be the
origin of the coordinate system and then X and Y are normal (0,25) and normal distributions,
respectively. Using the formula for a linear combination of normal variables, we obtain that (X −Y) is...
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