Parental Generatin (P) Cross - Pure Wildtype x Pure Short-winged Parent genotypes: __ x _- Genotypic ratio: Phenotypic ratio: First Filial (F1) Cross - F1 x F1 Parent genotypes: __x _- Genotypic...



use the results in the graph/table to answer the following questions


  Let L = wildtype (long) wings and l = short wings.


For the F1 generation cross
1.  Identify the genotype of each parent
2.  Create a Punnett square to explain your results
3.  Write the genotypic and phenotypic ratios



Parental Generatin (P) Cross - Pure Wildtype x Pure Short-winged<br>Parent genotypes: __ x _-<br>Genotypic ratio:<br>Phenotypic ratio:<br>First Filial (F1) Cross - F1 x F1<br>Parent genotypes: __x _-<br>Genotypic ratio:<br>Phenotypic ratio:<br>

Extracted text: Parental Generatin (P) Cross - Pure Wildtype x Pure Short-winged Parent genotypes: __ x _- Genotypic ratio: Phenotypic ratio: First Filial (F1) Cross - F1 x F1 Parent genotypes: __x _- Genotypic ratio: Phenotypic ratio:
Parental Generaton (P) Cross - Pure Wildtype x Pure Short-winged<br>Female Parent Male Parent<br>Predicted F1 Ratio<br>Actual F1 Results<br>Pure Wildtype Pure Short Wing Wildtype<br>Wing<br>300<br>Wildtype<br>500<br>Short<br>Short<br>First Filial (F1) Cross - F1 x F1<br>Female Parent Male Parent<br>Predicted F2 Ratio<br>Actual F2 Results<br>F1 Wildtype<br>Wing<br>F1 Wildtype<br>Wing<br>Wildtype<br>300<br>Wildtype<br>380<br>Short<br>60<br>Short<br>120<br>

Extracted text: Parental Generaton (P) Cross - Pure Wildtype x Pure Short-winged Female Parent Male Parent Predicted F1 Ratio Actual F1 Results Pure Wildtype Pure Short Wing Wildtype Wing 300 Wildtype 500 Short Short First Filial (F1) Cross - F1 x F1 Female Parent Male Parent Predicted F2 Ratio Actual F2 Results F1 Wildtype Wing F1 Wildtype Wing Wildtype 300 Wildtype 380 Short 60 Short 120

Jun 11, 2022
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