Page 211: Only solve exercises 10, 15 and 22 Page 221 solve: exercises 5 to 12 and then only exercises 30 and 35 Page 228: solve 13, 15 and 18 This table is the one they refer to in a previous...

Section1
10)
    
    X
    P(X=x)
    Xi*Pi
    Xi^2*Pi
    
    0
    0.0000
    0.000
    0.000
    
    1
    0.0001
    0.000
    0.000
    
    2

    0.0006
    0.001
    0.002
    
    3
    0.0387
    0.116
    0.348
    
    4
    0.9606
    3.8424
    15.3696
    
     
     
     
     
    
     
     
     
     
    
     
     
     
     
    
     
     
     
     
    sum
     
    1
    3.9598
    15.7204
E(X) = sum(Xi*Pi) = 3.9598
V(X) = sum(Xi^2*Pi) - mean^2
V(X) = 15.7204-3.9598^2
V(X) = 0.04038396
sd = sqrt(Var(X))
sd = sqrt(0.04038)
sd = 0.20096
15)
a)
P(X=x) = nCx * p^x * q^(n-x)    
P=    80.00%
n=    12
P(X=8) = BINOM.DIST(8,12,0.8,FALSE)
P(X=8) = 0.132875551
Since the probability P(x=8) is greater than 0.05, the result of 8 Mexican Americans among 12 jurors is not considered as usually low.
b)
there is 13% change that result of 8 Mexican Americans among 12 jurors. Since this probability is greater than 5%, I can say that selection process doesn’t discriminate against Mexican Americans.
22)
X be a random variable depicting the number of girls in a family. X follows binomial with n=4 and p=50%.
    X=x
    P(X=x)
    P(X=x)
    0
     =BINOM.DIST(0,4,0.5,FALSE)
    0.0625
    1
     =BINOM.DIST(1,4,0.5,FALSE)
    0.25
    2
     =BINOM.DIST(2,4,0.5,FALSE)
    0.375
    3
    ...