= P (Z %| Click to view page 1 of the table, Click to view page 2 of the table. a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as needed.) Ask a...


= P (Z < 2)<br>The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15<br>days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the<br>lowest 3%, then the baby is premature. Find the length that separates premature babies from those who are not<br>premature.<br>= 0.9773<br>(7 ><br>%|<br>Click to view page 1 of the table, Click to view page 2 of the table.<br>a. The probability that a pregnancy will last 309 days or longer is<br>(Round to four decimal places as needed.)<br>Ask a question<br>Enter your answer in the answer box and then click Check Answer.<br>1 part<br>remaining<br>Clear All<br>Check Answer<br>P Type here to search<br>hp<br>

Extracted text: = P (Z < 2)="" the="" lengths="" of="" pregnancies="" are="" normally="" distributed="" with="" a="" mean="" of="" 268="" days="" and="" a="" standard="" deviation="" of="" 15="" days.="" a.="" find="" the="" probability="" of="" a="" pregnancy="" lasting="" 309="" days="" or="" longer.="" b.="" if="" the="" length="" of="" pregnancy="" is="" in="" the="" lowest="" 3%,="" then="" the="" baby="" is="" premature.="" find="" the="" length="" that="" separates="" premature="" babies="" from="" those="" who="" are="" not="" premature.="0.9773" (7=""> %| Click to view page 1 of the table, Click to view page 2 of the table. a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as needed.) Ask a question Enter your answer in the answer box and then click Check Answer. 1 part remaining Clear All Check Answer P Type here to search hp

Jun 03, 2022
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