Oz= 2.50 and a p-value of (1-.9938) .0062

Oz= 2.50 and a p-value of (1-.9938)<br>.0062 < 05<br>So there is sufficient evidence to support the alternative hypothesis that the mean price of<br>gasoline in California is greater than the national average of $2.86.<br>Oz- 2.50 and a p-value of.9938<br>.9938 05<br>So there is not sufficient evidence to support the alternative hypothesis that the mean amount<br>of money spent on back to school supplies is greater than $606.40.<br>

Extracted text: Oz= 2.50 and a p-value of (1-.9938) .0062 < 05="" so="" there="" is="" sufficient="" evidence="" to="" support="" the="" alternative="" hypothesis="" that="" the="" mean="" price="" of="" gasoline="" in="" california="" is="" greater="" than="" the="" national="" average="" of="" $2.86.="" oz-="" 2.50="" and="" a="" p-value="" of.9938="" .9938="" 05="" so="" there="" is="" not="" sufficient="" evidence="" to="" support="" the="" alternative="" hypothesis="" that="" the="" mean="" amount="" of="" money="" spent="" on="" back="" to="" school="" supplies="" is="" greater="" than="">

Jun 01, 2022

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Oz= 2.50 and a p-value of (1-.9938) .0062

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