One-Sample Statistics Std. Deviation Std. Error Mean Mean for profit=1, nonprofit and GV=0 400 .7075 .45548 .02277 One-Sample Test Test Value = 0 95% Confidence Interval of the Difference Sig. (2-...


What would be an appropriate test to answer the research question below please explain why utilizing images attached?


A health care researcher would like to answer the following research question: On average, are for-profit nursing homes larger (based on total number of beds) than facilities of another type (non-profit and governmental)?


One-Sample Statistics<br>Std.<br>Deviation<br>Std. Error<br>Mean<br>Mean<br>for profit=1, nonprofit<br>and GV=0<br>400<br>.7075<br>.45548<br>.02277<br>One-Sample Test<br>Test Value = 0<br>95% Confidence Interval of<br>the Difference<br>Sig. (2-<br>tailed)<br>Mean<br>Difference<br>df<br>Lower<br>Upper<br>for profit=1, nonprofit<br>and GV=0<br>31.066<br>399<br>.000<br>.70750<br>.6627<br>.7523<br>One-Sample Effect Sizes<br>Standardizera<br>95% Confidence Interval<br>Point<br>Estimate<br>Lower<br>Upper<br>for profit=1, nonprofit<br>and GV=0<br>Cohen's d<br>.45548<br>1.553<br>1.407<br>1.698<br>Hedges' correction<br>.45634<br>1.550<br>1.405<br>1.695<br>a. The denominator used in estimating the effect sizes.<br>Cohen's d uses the sample standard deviation.<br>Hedges' correction uses the sample standard deviation, plus a correction factor.<br>

Extracted text: One-Sample Statistics Std. Deviation Std. Error Mean Mean for profit=1, nonprofit and GV=0 400 .7075 .45548 .02277 One-Sample Test Test Value = 0 95% Confidence Interval of the Difference Sig. (2- tailed) Mean Difference df Lower Upper for profit=1, nonprofit and GV=0 31.066 399 .000 .70750 .6627 .7523 One-Sample Effect Sizes Standardizera 95% Confidence Interval Point Estimate Lower Upper for profit=1, nonprofit and GV=0 Cohen's d .45548 1.553 1.407 1.698 Hedges' correction .45634 1.550 1.405 1.695 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation. Hedges' correction uses the sample standard deviation, plus a correction factor.
One-Sample Statistics<br>Std.<br>Deviation<br>Std. Error<br>Mean<br>Mean<br>Total Number of Beds<br>400 108.13<br>53.642<br>2.682<br>One-Sample Test<br>Test Value = 0<br>95% Confidence Interval of<br>the Difference<br>Sig. (2-<br>tailed)<br>Mean<br>Difference<br>df<br>Lower<br>Upper<br>Total Number of Beds<br>40.316<br>399<br>.000<br>108.133<br>102.86<br>113.41<br>One-Sample Effect Sizes<br>Standardizera<br>95% Confidence Interval<br>Point<br>Estimate<br>Lower<br>Upper<br>Total Number of Beds Cohen's d<br>53.642<br>2.016<br>1.845<br>2.186<br>Hedges' correction<br>53.743<br>2.012<br>1.841<br>2.182<br>a. The denominator used in estimating the effect sizes.<br>Cohen's d uses the sample standard deviation.<br>Hedges' correction uses the sample standard deviation, plus a correction factor.<br>

Extracted text: One-Sample Statistics Std. Deviation Std. Error Mean Mean Total Number of Beds 400 108.13 53.642 2.682 One-Sample Test Test Value = 0 95% Confidence Interval of the Difference Sig. (2- tailed) Mean Difference df Lower Upper Total Number of Beds 40.316 399 .000 108.133 102.86 113.41 One-Sample Effect Sizes Standardizera 95% Confidence Interval Point Estimate Lower Upper Total Number of Beds Cohen's d 53.642 2.016 1.845 2.186 Hedges' correction 53.743 2.012 1.841 2.182 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation. Hedges' correction uses the sample standard deviation, plus a correction factor.
Jun 09, 2022
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