of the n meshes. Use Ohm's law to meshes, a terms of the mesh currents. ultaneous equations to get the mesh www Example 1.7 Calculate the power supplied or absorbed by each element in Fig. 1.15....

Extracted text: of the n meshes. Use Ohm's law to meshes, a terms of the mesh currents. ultaneous equations to get the mesh www Example 1.7 Calculate the power supplied or absorbed by each element in Fig. 1.15. Solution: We apply the sign convention for power shown in Figs. 1.8 and 1.9. For Pi, the 5-A current is out of the positive terminal (or into the negative terminal); hence, 1-5A P2 12 V 8V P P1 = 20(-5) =-100 W Supplied power 20 V P3 0.2) For p2 and p3, the current flows into the positive terminal of the ele- ment in each case. P2 = 12(5) = 60 W Absorbed power Figure 1.15 For Example 1.7. P3 = 8(6) = 48 W Absorbed power For P4, we should note that the voltage is 8 V (positive at the top), the same as the voltage for p3, since both the passive element and the dependent source are connected to the same terminals. (Remember that voltage is always measured across an element in a circuit.) Since the current flows out of the positive terminal, P4 = 8(-0.21) = 8(-0.2 x 5)= -8 W Supplied power We should observe that the 20-V independent voltage source and 0.21 dependent current source are supplying power to the rest of the network, while the two passive elements are absorbing power. Also, Pi + P2 + P3 + p4 = -100 + 60 + 48-8 0 In agreement with Eq. (1.8), the total power supplied equals the total power absorbed. Practice Problem 1.7 Compute the power absorbed or supplied by each component of the