O YouTube O Mastering Biology -- Where are the deer? Random samples of square-kllometcr plots were taken in different ecologieal Incations of a national park. The deer counts per square kliometer were...


O YouTube<br>O Mastering Biology --<br>Where are the deer? Random samples of square-kllometcr plots were taken in different ecologieal Incations of a national park. The deer counts per square kliometer were recorded and are shown in the following<br>table.<br>Mountain<br>Brush<br>Sagebrush<br>Grassland<br>Pinon<br>Juniper<br>35<br>17<br>27<br>57<br>4<br>16<br>13<br>32<br>21<br>Shall we reject or accupt the claim that there is no ditterence in the inedi number of deer per square kilometer in these different eco logical locatinns? Use a 5% level of signilicance.<br>(a) What is the level of signiticance?<br>State the null and alternate hypotheses.<br>O H: 1 - 2 - si H: All three means are different<br>O lo: 4 = , - s; H: AL least twn meaıns are equal.<br>O Ho: - H2 = , H: Nol all the means are ecual.<br>O H: H1 - H2 - 13; H1: Exactly two means are equal.<br>(b) Find SSTOT SSBET, and SSw atid check that SSTOT - SSgErI SSw. (Use 3 decimal places)<br>SSor-<br>SSBET =<br>SSw-<br>Find d.1.eeT, d.f.w, MST, and MSw. (Use 2 decimal places for MSu, and MSw-)<br>dfr-<br>df w%=<br>MSppT<br>MSw-<br>Find the value of the sample F statistic. (Use 3 decirnal places.)<br>梦 0<br>19 AM<br>7/19/2021<br>63°F<br>P Type here to search<br>

Extracted text: O YouTube O Mastering Biology -- Where are the deer? Random samples of square-kllometcr plots were taken in different ecologieal Incations of a national park. The deer counts per square kliometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 35 17 27 57 4 16 13 32 21 Shall we reject or accupt the claim that there is no ditterence in the inedi number of deer per square kilometer in these different eco logical locatinns? Use a 5% level of signilicance. (a) What is the level of signiticance? State the null and alternate hypotheses. O H: 1 - 2 - si H: All three means are different O lo: 4 = , - s; H: AL least twn meaıns are equal. O Ho: - H2 = , H: Nol all the means are ecual. O H: H1 - H2 - 13; H1: Exactly two means are equal. (b) Find SSTOT SSBET, and SSw atid check that SSTOT - SSgErI SSw. (Use 3 decimal places) SSor- SSBET = SSw- Find d.1.eeT, d.f.w, MST, and MSw. (Use 2 decimal places for MSu, and MSw-) dfr- df w%= MSppT MSw- Find the value of the sample F statistic. (Use 3 decirnal places.) 梦 0 19 AM 7/19/2021 63°F P Type here to search
O https://www.webassign.net//web/Student/Assignment-Responses/submit?dep-26829196&tags-aulisaver<br>B YouTube<br>O Mastering Biology .<br>What are the degrees of Treedom?<br>(numerator)<br>(denominator)<br>(c) Find the P value of the sample lest slalistic.<br>O P-value > 0.100<br>O 0.050 < P-value < 0.100<br>O 0.025 < P value < 0.050<br>O 0.010 < P value < 0.025<br>O 0.001 < P value < 0.010<br>O Pvalue < 0.001<br>(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?<br>O Sirnce the p-value is greater than the level of signiticance al a - 0.05, wo de not reject Hp.<br>O Since the P-value is less than or equal to the level of signilicance at e - 0.05, we reject Hg-<br>O Since the P-value is greater than the level of significarice al a - 0.05, we reject He.<br>O Since the P-value is less than or equal to the level of significance at a = 0.05, we do nct reject Hg-<br>(e) Interpret your conclusion in the context of the application.<br>OAt the 5% level of significance there is insufficlent evidence to conclude thal Lhe mearns are nol all equal.<br>O At the 5% level of significance there is sufficient eviderice to conclude that the means are not all equal.<br>O At the 5% level of significance there is insufficient vidence to conclude that the means are all equal.<br>Oat the 5% level of significance there is sufficient evidence to conclude that the means are all equal.<br>(f) Make a summary table for your ANOVA test.<br>Degrees of<br>Freedom<br>Source of<br>Sum of<br>F<br>Test<br>MS<br>P Value<br>Variation<br>Between groups<br>Within groups<br>Squares<br>Ratlo<br>Decision<br>-Solect<br>Select<br>v.<br>Tatall<br>AM<br>7/19/2021<br>P Type here to search<br>63<br>

Extracted text: O https://www.webassign.net//web/Student/Assignment-Responses/submit?dep-26829196&tags-aulisaver B YouTube O Mastering Biology . What are the degrees of Treedom? (numerator) (denominator) (c) Find the P value of the sample lest slalistic. O P-value > 0.100 O 0.050 < p-value="">< 0.100="" o="" 0.025="">< p="" value="">< 0.050="" o="" 0.010="">< p="" value="">< 0.025="" o="" 0.001="">< p="" value="">< 0.010="" o="" pvalue="">< 0.001 (d) based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? o sirnce the p-value is greater than the level of signiticance al a - 0.05, wo de not reject hp. o since the p-value is less than or equal to the level of signilicance at e - 0.05, we reject hg- o since the p-value is greater than the level of significarice al a - 0.05, we reject he. o since the p-value is less than or equal to the level of significance at a = 0.05, we do nct reject hg- (e) interpret your conclusion in the context of the application. oat the 5% level of significance there is insufficlent evidence to conclude thal lhe mearns are nol all equal. o at the 5% level of significance there is sufficient eviderice to conclude that the means are not all equal. o at the 5% level of significance there is insufficient vidence to conclude that the means are all equal. oat the 5% level of significance there is sufficient evidence to conclude that the means are all equal. (f) make a summary table for your anova test. degrees of freedom source of sum of f test ms p value variation between groups within groups squares ratlo decision -solect select v. tatall am 7/19/2021 p type here to search 63 0.001="" (d)="" based="" on="" your="" answers="" in="" parts="" (a)="" to="" (c),="" will="" you="" reject="" or="" fail="" to="" reject="" the="" null="" hypothesis?="" o="" sirnce="" the="" p-value="" is="" greater="" than="" the="" level="" of="" signiticance="" al="" a="" -="" 0.05,="" wo="" de="" not="" reject="" hp.="" o="" since="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" level="" of="" signilicance="" at="" e="" -="" 0.05,="" we="" reject="" hg-="" o="" since="" the="" p-value="" is="" greater="" than="" the="" level="" of="" significarice="" al="" a="" -="" 0.05,="" we="" reject="" he.="" o="" since="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" level="" of="" significance="" at="" a="0.05," we="" do="" nct="" reject="" hg-="" (e)="" interpret="" your="" conclusion="" in="" the="" context="" of="" the="" application.="" oat="" the="" 5%="" level="" of="" significance="" there="" is="" insufficlent="" evidence="" to="" conclude="" thal="" lhe="" mearns="" are="" nol="" all="" equal.="" o="" at="" the="" 5%="" level="" of="" significance="" there="" is="" sufficient="" eviderice="" to="" conclude="" that="" the="" means="" are="" not="" all="" equal.="" o="" at="" the="" 5%="" level="" of="" significance="" there="" is="" insufficient="" vidence="" to="" conclude="" that="" the="" means="" are="" all="" equal.="" oat="" the="" 5%="" level="" of="" significance="" there="" is="" sufficient="" evidence="" to="" conclude="" that="" the="" means="" are="" all="" equal.="" (f)="" make="" a="" summary="" table="" for="" your="" anova="" test.="" degrees="" of="" freedom="" source="" of="" sum="" of="" f="" test="" ms="" p="" value="" variation="" between="" groups="" within="" groups="" squares="" ratlo="" decision="" -solect="" select="" v.="" tatall="" am="" 7/19/2021="" p="" type="" here="" to="" search="">
Jun 08, 2022
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