Extracted text: O YouTube O Mastering Biology -- Where are the deer? Random samples of square-kllometcr plots were taken in different ecologieal Incations of a national park. The deer counts per square kliometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 35 17 27 57 4 16 13 32 21 Shall we reject or accupt the claim that there is no ditterence in the inedi number of deer per square kilometer in these different eco logical locatinns? Use a 5% level of signilicance. (a) What is the level of signiticance? State the null and alternate hypotheses. O H: 1 - 2 - si H: All three means are different O lo: 4 = , - s; H: AL least twn meaıns are equal. O Ho: - H2 = , H: Nol all the means are ecual. O H: H1 - H2 - 13; H1: Exactly two means are equal. (b) Find SSTOT SSBET, and SSw atid check that SSTOT - SSgErI SSw. (Use 3 decimal places) SSor- SSBET = SSw- Find d.1.eeT, d.f.w, MST, and MSw. (Use 2 decimal places for MSu, and MSw-) dfr- df w%= MSppT MSw- Find the value of the sample F statistic. (Use 3 decirnal places.) 梦 0 19 AM 7/19/2021 63°F P Type here to search
Extracted text: O https://www.webassign.net//web/Student/Assignment-Responses/submit?dep-26829196&tags-aulisaver B YouTube O Mastering Biology . What are the degrees of Treedom? (numerator) (denominator) (c) Find the P value of the sample lest slalistic. O P-value > 0.100 O 0.050 < p-value="">< 0.100="" o="" 0.025="">< p="" value="">< 0.050="" o="" 0.010="">< p="" value="">< 0.025="" o="" 0.001="">< p="" value="">< 0.010="" o="" pvalue="">< 0.001 (d) based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? o sirnce the p-value is greater than the level of signiticance al a - 0.05, wo de not reject hp. o since the p-value is less than or equal to the level of signilicance at e - 0.05, we reject hg- o since the p-value is greater than the level of significarice al a - 0.05, we reject he. o since the p-value is less than or equal to the level of significance at a = 0.05, we do nct reject hg- (e) interpret your conclusion in the context of the application. oat the 5% level of significance there is insufficlent evidence to conclude thal lhe mearns are nol all equal. o at the 5% level of significance there is sufficient eviderice to conclude that the means are not all equal. o at the 5% level of significance there is insufficient vidence to conclude that the means are all equal. oat the 5% level of significance there is sufficient evidence to conclude that the means are all equal. (f) make a summary table for your anova test. degrees of freedom source of sum of f test ms p value variation between groups within groups squares ratlo decision -solect select v. tatall am 7/19/2021 p type here to search 63 0.001="" (d)="" based="" on="" your="" answers="" in="" parts="" (a)="" to="" (c),="" will="" you="" reject="" or="" fail="" to="" reject="" the="" null="" hypothesis?="" o="" sirnce="" the="" p-value="" is="" greater="" than="" the="" level="" of="" signiticance="" al="" a="" -="" 0.05,="" wo="" de="" not="" reject="" hp.="" o="" since="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" level="" of="" signilicance="" at="" e="" -="" 0.05,="" we="" reject="" hg-="" o="" since="" the="" p-value="" is="" greater="" than="" the="" level="" of="" significarice="" al="" a="" -="" 0.05,="" we="" reject="" he.="" o="" since="" the="" p-value="" is="" less="" than="" or="" equal="" to="" the="" level="" of="" significance="" at="" a="0.05," we="" do="" nct="" reject="" hg-="" (e)="" interpret="" your="" conclusion="" in="" the="" context="" of="" the="" application.="" oat="" the="" 5%="" level="" of="" significance="" there="" is="" insufficlent="" evidence="" to="" conclude="" thal="" lhe="" mearns="" are="" nol="" all="" equal.="" o="" at="" the="" 5%="" level="" of="" significance="" there="" is="" sufficient="" eviderice="" to="" conclude="" that="" the="" means="" are="" not="" all="" equal.="" o="" at="" the="" 5%="" level="" of="" significance="" there="" is="" insufficient="" vidence="" to="" conclude="" that="" the="" means="" are="" all="" equal.="" oat="" the="" 5%="" level="" of="" significance="" there="" is="" sufficient="" evidence="" to="" conclude="" that="" the="" means="" are="" all="" equal.="" (f)="" make="" a="" summary="" table="" for="" your="" anova="" test.="" degrees="" of="" freedom="" source="" of="" sum="" of="" f="" test="" ms="" p="" value="" variation="" between="" groups="" within="" groups="" squares="" ratlo="" decision="" -solect="" select="" v.="" tatall="" am="" 7/19/2021="" p="" type="" here="" to="" search=""> 0.001 (d) based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? o sirnce the p-value is greater than the level of signiticance al a - 0.05, wo de not reject hp. o since the p-value is less than or equal to the level of signilicance at e - 0.05, we reject hg- o since the p-value is greater than the level of significarice al a - 0.05, we reject he. o since the p-value is less than or equal to the level of significance at a = 0.05, we do nct reject hg- (e) interpret your conclusion in the context of the application. oat the 5% level of significance there is insufficlent evidence to conclude thal lhe mearns are nol all equal. o at the 5% level of significance there is sufficient eviderice to conclude that the means are not all equal. o at the 5% level of significance there is insufficient vidence to conclude that the means are all equal. oat the 5% level of significance there is sufficient evidence to conclude that the means are all equal. (f) make a summary table for your anova test. degrees of freedom source of sum of f test ms p value variation between groups within groups squares ratlo decision -solect select v. tatall am 7/19/2021 p type here to search 63>