O Part (C) Which distribution should you use for this problem? (Round your answer to four decimal places.) P'- n 430 Enter a number. Explain your choice. The Student's t-distribution should be used...

Suppose that insurance companies did a survey. They randomly surveyed 430 drivers and found that 350 claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up.


NOTE: If you are using a Student'st-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)

Extracted text: O Part (C) Which distribution should you use for this problem? (Round your answer to four decimal places.) P'- n 430 Enter a number. Explain your choice. The Student's t-distribution should be used because we do not know the standard deviation. The Student's t-distribution should be used because npq s 10, which implies a small sample. The binomial distribution should be used because there are two outcomes, buckle up or do not buckle up. The normal distribution should be used because we are interested in proportions and the sample size is large. Correct! We use the standard normal distribution to create confidence intervals about the population proportion. O Part (d) Construct a 95% confidence interval for the population proportion who claim they always buckle up. (1) State the confidence interval. (Round your answers to four decimal places.) (ii) Sketch the graph. a a C.L. = 2 P' (ii) Calculate the error bound. (Round your answer to four decimal places.)


Extracted text: (iii) Round your answer to four decimal places. (rounded to four decimal places) p'=