O) at 25°C and 100 kPa is to be dehumidified soMoistDehumidifiedthat during its passage through za large cold room used for storage excess,ice formation can be avoided on the chilling coils in the...


Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so<br>Moist<br>Dehumidified<br>that during its passage through za large cold room used for storage excess,<br>ice formation can be avoided on the chilling coils in the room. Two<br>suggestions have been offered:<br>(1) Cooling the moist air at constant pressure<br>(2) Compressing the moist air at constant temperature<br>1. If 60% of the initial water in the entering moist air is to be condensed<br>out, to what temperature should the air in process (1) be cooled?<br>2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)?<br>PROCESS<br>air<br>air<br>Condensed<br>water<br>Additional information:<br>В<br>log 10 Psat [mm Hg] = A –<br>Component<br>A<br>В<br>T[°C] + C<br>Water<br>18<br>8.14019<br>1810.94<br>244.485<br>

Extracted text: Moist air (2.27 mol% H>O) at 25°C and 100 kPa is to be dehumidified so Moist Dehumidified that during its passage through za large cold room used for storage excess, ice formation can be avoided on the chilling coils in the room. Two suggestions have been offered: (1) Cooling the moist air at constant pressure (2) Compressing the moist air at constant temperature 1. If 60% of the initial water in the entering moist air is to be condensed out, to what temperature should the air in process (1) be cooled? 2. What pressure should the moist air in process (2) reach for the same percent removal of water (60%)? PROCESS air air Condensed water Additional information: В log 10 Psat [mm Hg] = A – Component A В T[°C] + C Water 18 8.14019 1810.94 244.485
Jun 11, 2022
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