Now there are 10 outcomes in B (for example (0,1,0,1,0)), each having probability (1 − p)3p2. Hence P(B) = 10(1 − p)3p2.
2. This happens if and only if the experiment fails on Monday,. . . , Saturday, and is a success on Sunday. This has probability p(1 − p)6 to happen.
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