Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then, 20 40 60 80 100 S 5.56 11.11 16.67 22.22 27.78 d 5.1 13.7 27.2 44.2 66.4 Step 2 use the regression...

how to get the value of 0.071s^2 + 0.389s + 0.727 through regression? can someone explain?

Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then,<br>20<br>40<br>60<br>80<br>100<br>S<br>5.56<br>11.11<br>16.67<br>22.22<br>27.78<br>d<br>5.1<br>13.7<br>27.2<br>44.2<br>66.4<br>Step 2<br>use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + c<br>then,<br>d (s) = 0.071s² + 0. 389s + 0. 727<br>d(s)<br>Now, calculating the minimum value of T then substitute d (s) into the equation T (s) =<br>+ 55<br>T (s) = (0.071s2² + 0. 389s + 0. 727) + 3<br>5.5<br>T (s) = 0.071s + 0. 389 + 6.227<br>

Extracted text: Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then, 20 40 60 80 100 S 5.56 11.11 16.67 22.22 27.78 d 5.1 13.7 27.2 44.2 66.4 Step 2 use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + c then, d (s) = 0.071s² + 0. 389s + 0. 727 d(s) Now, calculating the minimum value of T then substitute d (s) into the equation T (s) = + 55 T (s) = (0.071s2² + 0. 389s + 0. 727) + 3 5.5 T (s) = 0.071s + 0. 389 + 6.227

Jun 10, 2022

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Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then, 20 40 60 80 100 S 5.56 11.11 16.67 22.22 27.78 d 5.1 13.7 27.2 44.2 66.4 Step 2 use the regression...

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