Noise and Stress In Exercise, you compared the effect of stress in the form of noise on the ability to perform a simple task. Seventy subjects were divided into two groups; the first group of 30...

1 answer below »


Noise and Stress
In Exercise, you compared the effect of stress in the form of noise on the ability to perform a simple task. Seventy subjects were divided into two groups; the first group of 30 subjects acted as a control, while the second group of 40 was the experimental group. Although each subject performed the task in the same control room, each of the experimental group subjects had to perform the task while loud rock music was played. The time to finish the task was recorded for each subject and the following summary was obtained:




























Control



Experimental



n



30



40



15 minutes



23 minutes



s



4 minutes



10 minutes



a. Is there sufficient evidence to indicate that the average time to complete the task was longer for the experimental “rock music” group? Test at the 1% level of significance.


b. Construct a 99% one-sided upper bound for the difference (control - experimental) in average times for the two groups. Does this interval confirm your conclusions in part a?



Exercise:



Noise and Stress
To compare the effect of stress in the form of noise on the ability to perform a simple task, 70 subjects were divided into two groups. The first group of 30 subjects acted as a control, while the second group of 40 were the experimental group. Although each subject performed the task in the same control room, each of the experimental group subjects had to perform the task while loud rock music was played. The time to finish the task was recorded for each subject and the following summary was obtained:




























Control



Experimental



n



30



40



15 minutes



23 minutes



s



4 minutes



10 minutes


Answered Same DayDec 24, 2021

Answer To: Noise and Stress In Exercise, you compared the effect of stress in the form of noise on the ability...

David answered on Dec 24 2021
120 Votes
Ho: µE = µ C
H1: µE > µ C
Sample difference 23-15 = 8
Standard error = Se = ( 42/30 +102/40)^.5 =
1.74
Test value = ( 8/1.74) = 4.59
The critical z value is for 99% confidence =2.33. we use z value as the samples are large – both are 30 and 40 so normal distribution can be used.
Since test...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here