Nicole Becker – Assignment 9
Complete the following textbook exercises:
2, 12 and 14
It is a decision under risk problem. Our state of nature is .7 and .3 and decision to make is which bottle to choose
Payoff table
State of nature
probability
Conditional payoff
returnable
Non returnable
Law passed
.7
80
25
Not passed
.3
40
60
68
25.5
As expected monetary payoff for returnable= .7*80+.3+40=68 is greater than EMP of non returnable bottles=.7*25+.3*60=25.5. so choosing returnable bottles is wise.
State of nature is good or bad weather with probabilities .4 and .6 respectively.
Total cost to travel by any means is= 75*time taken in journey+ cost of travel by that means
Payoff table
State of nature
Probability
(i)
Conditional probabilities in terms of monerty value $ (ii)
(i)*(ii)
Under perfect information
Car
Train
Plane
Car
Train
Plane
Minimum payoff(iii)
(i)*(iii)
Good weather
0.4
370
490
366.25
148
196
146.5
366.25
146.5
Bad weather
0.6
445
502.5
372.5
267
301.5
223.5
372.5
372.5
total
415
497.5
370
370
As EMV of traveling by plane is lowest this is the decision financial executive should choose.
So expected value of perfect information is =370-370=0.
C =20*0.5=10$ for all parts inspection
C=20*18*Sj= 360*Sj for none inspection
a)
State of
Probability of state
Inspecting (ii)
(i)*(ii)
Under perfect
nature
of nature (i)
information
All parts
None parts
All parts
None parts
Maximum payoff(iii)
(i)*(iv)
0.02
.7
10
7.2
7
5.04
10
7
0.04
.2
10
14.4
2
2.88
14.4
2.88
0.06
.1
10
21.6
1
2.16
21.6
2.16
10
10.08
12.04
b) Expected monetary value for all part inspection is less so this decision is better.
c) expected value of perfect information= 12.04-10= 2.02