MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER EXAMPLE 4 Find the volume of the solid that lies under the paraboloid z = 5x2 + 5y2, above the xy-plane, and inside the cylinder x2 + y2 = 2x. SOLUTION The...


MY NOTES<br>ASK YOUR TEACHER<br>PRACTICE ANOTHER<br>EXAMPLE 4<br>Find the volume of the solid that lies under the paraboloid z = 5x2 + 5y2, above the xy-plane, and inside the cylinder x2 + y2 = 2x.<br>SOLUTION<br>The solid lies above the disk D whose boundary circle has equation x2 + y? = 2x or, after completing the square,<br>+ y2 =<br>In polar coordinates we have x2 + y? =2 and x = r cos(0), so the boundary circle becomes r² = 2r cos(0), or r= 2 cos(0). Thus the disk D is given by<br>= {(r, 0) -1/2 s 0 S T/2, 0 srs 2<br>and, by this formula, we have<br>(5x + 5y2) dA<br>1/2 2 cos(@)<br>dr de<br>12 cos(8)<br>de<br>* T/2<br>cos (0) de<br>T/2<br>1 +<br>de<br>7/2<br>+2 cos(26) + 글(1+ cos(48)| d8<br>17/2<br>10/1<br>

Extracted text: MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER EXAMPLE 4 Find the volume of the solid that lies under the paraboloid z = 5x2 + 5y2, above the xy-plane, and inside the cylinder x2 + y2 = 2x. SOLUTION The solid lies above the disk D whose boundary circle has equation x2 + y? = 2x or, after completing the square, + y2 = In polar coordinates we have x2 + y? =2 and x = r cos(0), so the boundary circle becomes r² = 2r cos(0), or r= 2 cos(0). Thus the disk D is given by = {(r, 0) -1/2 s 0 S T/2, 0 srs 2 and, by this formula, we have (5x + 5y2) dA 1/2 2 cos(@) dr de 12 cos(8) de * T/2 cos (0) de T/2 1 + de 7/2 +2 cos(26) + 글(1+ cos(48)| d8 17/2 10/1

Jun 04, 2022
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