Module title: Research Methods and Analysis 2 Module code: 4PS046 Level 4 Resit details CW2: Portfolio of statistical exercises (40% weighting) Note the details of the assessment are as for the first...

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Answer To: Module title: Research Methods and Analysis 2 Module code: 4PS046 Level 4 Resit details CW2:...

Robert answered on Dec 20 2021
123 Votes
A1) Here we will use the chi square test of independence.
HO: There is no relation between sex category and spatial ability at age.

H1:There is a relation between sex category and spatial ability at age.
Test statistic: 


i i
ii
e
eo 22 )(
The SPSS output is attached:
Sex * SpAb8 Crosstabulation
Count
SpAb8
Total High Low
Sex Female 21 19 40
Male 20 20 40
Total 41 39 80
Chi-Square Tests
Value df
Asymp. Sig. (2-
sided)
Exact Sig. (2-
sided)
Exact Sig. (1-
sided)
Pearson Chi-Square .050
a
1 .823
Continuity Correction
b
.000 1 1.000
Likelihood Ratio .050 1 .823
Fisher's Exact Test 1.000 .500
Linear-by-Linear Association .049 1 .824
N of Valid Cases
b
80
a. 0 cells (.0%) have expected count less than 5. The minimum expected count is 19.50.
b. Computed only for a 2x2 table

From the chi-Square Tests table, we can see that the p value is 0.823, which is more than 0.05, thus
we conclude that there is no support for the idea that there are sex differences in high and low
spatial ability at age 8.
A2) Here we will use the independent sample t test .
Let
1 be the population mean time taken by those with high spatial ability and 2 be the mean
time taken by those with low spatial ability.
H0: 1 = 2
H1:
1  2
Test...
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