MIC 102 Introductory Microbiology | MIDTERM 2 Page 1 of 8 Spring 2020 NAME (all caps) ______________________________ STUDENT ID ______________ INSTRUCTIONS: Read the detailed exam instructions, which...

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MIC 102 Introductory Microbiology | MIDTERM 2 Page 1 of 8 Spring 2020 NAME (all caps) ______________________________ STUDENT ID ______________ INSTRUCTIONS: Read the detailed exam instructions, which are posted on Canvas > Assignment > Midterm 2, before starting this exam. Follow them carefully. • Write in your name and Student ID (above). • Read and sign the Academic Integrity Affirmation (below). • Write your responses by hand, in easy-to-read, high-contrast ink or pencil, and in reasonably-large font size. • Upload a high-quality scan of your answer form to Canvas > Gradescope > Midterm 2 before 10:30 AM on Wednesday, May 20. ACADEMIC INTEGRITY AFFIRMATION: As a student at UC Davis, I hold myself to a high standard of integrity. By signing and accepting the statement below, I reaffirm my pledge to act ethically and honor the UC Davis Code of Academic Conduct. I hereby verify that the work I submit is the result of my individual effort. I did not consult with or receive help from any person other than the instructor, nor did I help others. I also understand that disciplinary sanctions will be imposed if misconduct is determined to have taken place (up to an F in the course, up to dismissal from the University). FULL NAME (SIGNATURE) _________________________________________ https://ossja.ucdavis.edu/code-academic-conduct https://ossja.ucdavis.edu/code-academic-conduct MIC 102 Introductory Microbiology | MIDTERM 2 Page 2 of 8 Spring 2020 FACTORS INVOLVED IN DNA REPLICATION AND CELL DIVISION. 1. (4 pts) List four ways in which in vivo lagging-strand DNA replication is different from in vitro DNA replication (PCR): 2. (3 pts) The minCDE operon is shown above (link to EcoCyc genome view). How would the expression and localization of minC, minD, and minE be impacted if a 2000 bp (kbp) transposon inserted itself into minD? 3. (3 pts) Where is cell division most likely to occur in this transposon mutant (above): at the midpoint, near the ends of the cell, at multiple sites along the length of the cell, or nowhere (if cell division cannot occur in this mutant)? Explain your reasoning, including discussion of other factors that influence the site of cell division. https://ecocyc.org/ECOLI/NEW-IMAGE?type=LOCUS-POSITION&object=EG10597&chromosome=COLI-K12 MIC 102 Introductory Microbiology | MIDTERM 2 Page 3 of 8 Spring 2020 NECESSITY OF HELICASE ACTIVITY. 4. (1 pt) A researcher discovered a new antibacterial drug, ZipX, that inhibits all DNA and RNA helicase-type activity in bacterial cells. Describe the general function (catalytic activity) of a helicase. 5. (3 pts) For each cell process listed below, indicate whether or not that process would be directly impacted by ZipX in bacterial cells, and explain your reasoning. DNA repair Transcription Translation 6. (2 pts) Based solely on its mechanism of action and cellular target(s), predict whether the therapeutic index of ZipX would be high or low. Explain your answer. MIC 102 Introductory Microbiology | MIDTERM 2 Page 4 of 8 Spring 2020 THE IMPORTANCE OF BEING METHYLATED. 7. (1 pts) Describe the catalytic activities of a methylase (how it performs its function): 8. (4 pts) Predict the direct impact of a loss-of-function mutation in the methylase involved in each of the following processes. Your answer should discuss its impact on both the specific process and phenotype of the cell (e.g. growth, survival). A. DNA replication: B. Restriction-modification system: 9. (2 pt) Your father is a history teacher at a local elementary school, and is extremely vocal about how he hates “germs”. He tells you that, when the school opens again, he will stock his classroom with lots of antibacterial hand sanitizer, containing antibiotic-like chemicals, to “keep everyone healthy”. Briefly explain why this is not a good idea, using non-scientific terms such that a non-scientist could understand and explain it to others. [Based on a student-submitted question] MIC 102 Introductory Microbiology | MIDTERM 2 Page 5 of 8 Spring 2020 REGULATION OF THE LAC OPERON. 10. (3 pts) Sketch the lac operon, including only the listed elements (below) and labeling each. You may draw multiple copies of an individual element if appropriate. CRP-cAMP (bound to binding site), LacI (bound to binding site), lacY gene, lacZ gene, Shine-Dalgarno sequence, promoter, and transcriptional terminator. 11. (3 pts) Assume your drawing (above) represents the status of the operon in a live bacterial cell growing in culture. Based on the regulatory factors (above), indicate whether glucose and/or lactose are present in the media. Explain your answer. Setup: Use a codon chart to translate the following partial nucleotide sequence of the 5’ end of the lacI gene. Write the single letter amino acid code below the encoding nucleotides. (Codon chart posted on the Midterm 2 Canvas Assignment.) ATGACTTCTGTAACTCTTGCTCAG… 12. (1 pt) Translate the entire nucleotide sequence again, writing only the single letter amino acid codes, with the indicated replication error (emphasized in bold below). ATGACTTCTGTAAACTCTTGCTCAG… MIC 102 Introductory Microbiology | MIDTERM 2 Page 6 of 8 Spring 2020 13. (2 pt) Predict how this mutation will impact the structure and function of LacI. 14. (4 pt) Predict how this mutation will impact the cell with regard to its ability to catabolize lactose and relative growth rate. Explain your answer. A “WHO DUNNIT?” OF DNA TRANSFER. 15. (3 pt) A multi-stage experiment was conducted with two different species: a non- pathogenic strain of Buttiauxella agrestis (Ba) and a strain of Haemophilus influenzae (Hi) carrying a plasmid with a virulence gene (Hi/pVir). The cultures were treated as described for each stage (1-5, below), then inoculated into healthy mice. The mice were observed 24 hours later. 1. When Ba was inoculated → the mice lived 2. When Hi/pVir was inoculated → the mice died 3. When heat-killed Hi/pVir was inoculated → the mice lived 4. When Hi/pVir was mixed with Ba, the mixed cells were incubated for an hour, and then only the Ba cells were inoculated → the mice died 5. When Hi/pVir was first heat-killed before being mixed with live Ba, the mixed cells were incubated for an hour, and then only the Ba cells were inoculated → the mice lived Which was the method of DNA transfer: transformation, transduction, or conjugation? Explain your answer, including discussion of which species was the recipient and donor. MIC 102 Introductory Microbiology | MIDTERM 2 Page 7 of 8 Spring 2020 CONSIDER THE FOLLOWING BIOSYNTHETIC REACTION. (Link to MetaCyc Reaction, provided in case you wish to view a larger version of the image.) 16. (3 pt) Identify the precursor metabolite that became the ribose in the ATP and UTP during biosynthesis, and list the feature(s) of this precursor that make(s) it an appropriate starting molecule. NITROGEN FIXATION AND CYCLIC PHOTOSYNTHESIS. 17. (2 pt) Given that nitrogenase is inactivated by O2, would you expect expression of this enzyme to be induced or repressed by the presence of O2? Briefly explain your rationale. https://biocyc.org/META/NEW-IMAGE?type=REACTION&object=CTPSYN-RXN MIC 102 Introductory Microbiology | MIDTERM 2 Page 8 of 8 Spring 2020 18. Killem X is a chemical used to kill off photosynthetic organisms that perform cyclic photophosphorylation. Its mechanism of action is to oxidize the first complex in the cyclic photophosphorylation electron transport chain. A. (4 pt) How would oxidation of an electron transport chain component by Killem X lead to the death of an organism performing cyclic photosynthesis? B. (2 pt) Killem X is also a potent inhibitor of nitrogen-fixation by cyanobacteria. Explain why an inhibitor of cyclic photophosphorylation would also inhibit nitrogen fixation in these bacteria. [Based on a student-submitted question]
Answered Same DayMay 19, 2021

Answer To: MIC 102 Introductory Microbiology | MIDTERM 2 Page 1 of 8 Spring 2020 NAME (all caps)...

Swati answered on May 20 2021
143 Votes
Q1. List four ways in which in vivo lagging-strand DNA replication is different from in vitro DNA replication.
A1. DNA replication is the biological process in which two identical replicas are produced from the original DNA molecule. DNA consists of two complementary strands of double helix. During replication, these strands get separated and each of the strand acts as template to produce its counterpart. Lagging strand is that strand of DNA helix whose synthesis direction is oppos
ite to that of growing replication fork.
The ways in which in vivo lagging strand DNA replication is different from that of in vitro are as follows-
a) In vivo DNA replication is depends on complex and well defined set of enzymes and co-factors that have evolved during the S-phase of cell cycle. Whereas, in vitro DNA replication takes place in quite simple manner using smaller set of defined ingredients and reaction conditions.
b) In-vivo DNA replication takes place at normal body temperature whereas for In-vitro DNA replication, relatively high temperature is required to bring about the synthesis.
c) In-vivo DNA replication does lead to normal growth and DNA synthesis whereas there is exponential growth of DNA while carried out In-vitro leading to large amount of DNA synthesis.
d) During in vivo DNA replication, cell associated proteins act in concert to uncoil the stable a-helical DNA structure, break the hydrogen bonds between the purine and pyrimidine bases, and expose a DNA replication origin. In contrast, DNA required for In vitro DNA replication is separated from its chaperone proteins using chemical and/or enzymatic extraction methods, with the DNA then being separated into single strands via thermal disassociation.
Q2. The minCDE operon is shown above (link to EcoCyc genome view). How would the expression and localization of minC, minD, and minE be impacted if a 2000 bp (kbp) transposon inserted itself into minD?

A2. The Expression and localization of minC, mind and mine will be impacted to great extent by inserting a 2000bp (kbp) transposon into minD. The impacts are as follows-
a. DNA sequence will be changed leading to mutations which may activation of a gene expression. The chances of activation are more as the insertion is done in the same direction of operon that permits the read through transcription of quasi-essential or essential genes. 
b. There will be noticeable asymmetry in orientations of such insertions which are disrupting but they will avoid collision between read through transcription of minC, minE and adjacent genes.
c. This mutant formed due to insertion during lipid growth will produce shortened swarmer cells during differentiation leading to exhibition of decreased swarming motility.
Q3. Where is cell division most likely to occur in this transposon mutant (above): at the midpoint, near the ends of the cell, at multiple sites along the length of the cell, or nowhere (if cell division cannot occur in this mutant)? Explain your reasoning, including discussion of other factors that influence the site of cell division.
A3.- cell division in this transposon mutant is most likely to occur at near the ends of the cell leading to slightly enlarged cell. This is because
a. The Min system is comprised of three protein, minC, mind and min E whose oscillation prevents formation of Z ring at poles of rod shaped cells. MinC acts as the effector of this system by preventing FtsZ polymerization. MinD binds the cell membrane in an ATP-dependent manner, where it recruits MinC and activates it 25- to 50-fold. The ATPase activity of MinD, which causes it to disassociate with the cell membrane, is induced by MinE.
b. MinE, suppress the activity of MinCD and restricts cell division inhibition to one pole at a time and is responsible for the oscillating nature of the complex.
c. When MinE stimulates disassociation of the complex at one pole, MinD-ADP moves to the opposite pole, where it recruits MinC, and the process begins again. A min mutant produces anucleate minicells from the pole of a mother cell, which, as a result of minicell production, is slightly enlarged.
Q4. - A researcher discovered a new antibacterial drug, ZipX, that inhibits all DNA and RNA helicase-type activity in bacterial cells. Describe the general function (catalytic activity) of a helicase.
A4.- Helicase is an enzyme that functions by melting the hydrogen bonds that hold the DNA in double helix structure. This allows opening up of DNA to be available to bind with the drug leading to inhibitions of all DNA and RNA helicase type activities in bacterial cells. This way ZipX acts as antibacterial drug.
Q5. For each cell process listed below, indicate whether or not that process would be directly impacted by ZipX in bacterial cells, and explain your reasoning.
A5. – Helicases present in zipX...
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