Methane (CH«, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and 17.8 psia. a. Find the volumetric flow rate of CHa using the ideal gas law. b....

Extracted text: Methane (CH«, M = 16 g/mol) flows through a gas pipeline at a rate of 48 Ibm/h. If the gas is maintained at 86 °F and 17.8 psia. a. Find the volumetric flow rate of CHa using the ideal gas law. b. Find the volumetric flow rate of CH, using the combined gas law. At STP, 1 lb-mol of gas has a volume of 359 ft. C. Find the flow rate in standard cubic feet per hour (SCFH). The SCFH is defined as the hypothetical volumetric flow rate in ft/h if the same moles of gas were at STP. Solution: For item (a): The ideal gas law uses the moles instead of mass. Convert the mass flow rate to a molar flow rate. M Use the ideal gas law to solve for the volumetric flow rate. We use R = 10.73 ft²-psi/lb-mol-°R because of its compatibility with the other units. Convert "F to "R using T(°R] = T[°F] + 459.67. RT pV = ńRT → V =. For item (b): The combined gas law is shown below. At STP (1 atm = 14.7 psi pressure and 0 "C = 491.67 "R temperature), the volumetric flow rate of 1 Ib-mol/h of gas is 359 ft²/h. Note that n and T (for the actual conditions) have been computed previously in Item (a). pV PStpVSTP (17.8 psi)V (14.7 psi)(359 ft /h) (1 lb-mol/h)(491.67 °R) V = For item (c): The flow rate in SCFH is the hypothetical volumetric flow rate VSCFH if the same moles of gas in actual conditions i were subjected to the pressure and temperature at STP (PsTP = 14.7 psi, TSTp = 491.67 °R). When asked to report the flow rate in SCFH, replace the "ft°/h" unit with "SCFH" (ie., "1 SCFH"). PSTpVscau = iRTSTp → Vaczu = ARTSTP PSTP Note that Vscen is different from VSTP. VSTP is always paired with iStp = 1 lb-mol/h in AES units (or Vsrp = 22.4 L when nSTp = 1 mol in Sl units), whereas Vscru Uses the true or actual molar flow rate n.