MET330 20xx0xE Applied Fluid MechanicsInstructor: Instructors name Mid-Term Part 2 Review Assignment ProblemsNOTE: Handwritten work is not acceptable. All work must be typed and submitted on...

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Answer To: MET330 20xx0xE Applied Fluid MechanicsInstructor: Instructors name Mid-Term Part 2 Review...

Perla answered on Feb 08 2023
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MET330 20xx0xE Applied Fluid Mechanics
Instructor: Instructors name
Mid-Term Part 2
Review Assignment Problems
NOTE: Handwritten work is not acceptable. All work must be typed and submitted on a Word D
ocument.
a. Identify and list all variables from the problem.
b. Write the equation(s) you will use that are found in the textbook. Do not use any other equations.
c. Substitute your variables into the equation. YOU MUST INCLUDE UNITS IN ALL PLACES OF YOUR EQUATIONS.
d. You must show all of your work, even “simple” calculations. During your calculations, please use 3 decimal places or 3 significant decimal places. This does not apply to financial cost calculations.
e. Clearly identify your answer with correct units.

· CORRECT METHOD:
· INCORRECT METHOD: p2 = (W * a)/g + p1 = a^2 - Ap – μ = 0
Part2 (40 points)
Either in class open-book or take-home (to be release one lecture before the midterm in that case)
Problem 1
The specific gravity of benzene is 0.876. Calculate its specific weight and its density in U.S. Customary System units.
Given specific gravity of benzene is 0.876
Specific weight of benzene is given by the following equation
Where γ is specific weight, ρ is density of the substance and g is acceleration due to gravity.
From the given specific gravity,
the specific density of benzene = 0.876 x 1000 kg/m3 = 876 kg/m3
Acceleration due to gravity g = 9.81m/s2
Hence the specific weight of the benzene = 876 x 9.81 kg/m3 * m/s2 = 8593.56 N/m3 =8.593kN/m3
Problem 2
If milk has a specific gravity of 1.08, what is the pressure at the bottom of a milk can 550 mm deep?
Specific gravity of milk =1.08
Density of the milk = 1.08 X 1000kg/m3 =1080 kg/m3
The depth of the can = 550mm = 0.55m
The pressure at the bottom of the milk can,
P = ρ*g*H
P = 1080x 9.81 x 0.55 = 5827.14 N/m2 =5.827 kPa
Problem 3
For the differential manometer shown, calculate the pressure difference between points A and B. The specific gravity of the oil is 0.85.
From the given specific gravity of oil, its specific density = 0.85 x 1000kg/m3...
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