Math 13 Final Exam, Moodle Component 1. Out of 800 families with 6 children each, how many would you expect to have at least 2 girls? 2. A random sample of residents of Greenville was surveyed and the...

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Math 13 Final Exam, Moodle Component 1. Out of 800 families with 6 children each, how many would you expect to have at least 2 girls? 2. A random sample of residents of Greenville was surveyed and the average number of hours per week that they walk was recorded: 7 6 4 8 2 8 9 12 1 2 6 7 8 10 11 9 5 5 3 5 8 11 12 6 2 6 7 8 10 11 Use this data to find a 95% confidence interval for the mean number of hours of walking per resident per week for the entire population of Greenville. 3. John suspects that a pair of dice is loaded (unfair). To test his hypothesis he rolls the dice 72 times. A total of seven comes up fifteen times. Set a=0.05, state the null and alternate hypotheses, perform the calculations needed to arrive at a conclusion about the fairness of the dice and state your conclusion.


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Math 13 Final Exam, Moodle Component 1. Out of 800 families with 6 children each, how many would you expect to have at least 2 girls? 2. A random sample of residents of Greenville was surveyed and the average number of hours per week that they walk was recorded: 7 6 4 8 2 8 9 12 1 2 6 7 8 10 11 9 5 5 3 5 8 11 12 6 2 6 7 8 10 11 Use this data to find a 95% confidence interval for the mean number of hours of walking per resident per week for the entire population of Greenville. 3. John suspects that a pair of dice is loaded (unfair). To test his hypothesis he rolls the dice 72 times. A total of seven comes up fifteen times. Set a=0.05, state the null and alternate hypotheses, perform the calculations needed to arrive at a conclusion about the fairness of the dice and state your conclusion.



Answered Same DayDec 21, 2021

Answer To: Math 13 Final Exam, Moodle Component 1. Out of 800 families with 6 children each, how many would you...

David answered on Dec 21 2021
118 Votes
1) Given n=800 and p= probability of female birth= 1/2=q
Probability of 2 females in family of 8 i
s given by binomial distribution.
2 8 2
8
2
1 1
2 2
C

   
   
   

And P[x≥2]=1-P[x<2]=1-
2 8 2
8
2
1 1
2 2
C

   
   
   

2 8 2
2 6
8! 1 1
6!*2! 2 2
8*7 1 1 28
.11
2 2 2 256

   
    
   
   
     
   

So given frequency=800*0.11=87.5
So probability of atleast 2 female kids is 87.5/800=.11
2) Here we are given a sample of size n=30 as average number of hours per week by
resident of Greenville and we have to find confidence interval mean number...
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