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Answered 1 days AfterMay 31, 2022

Answer To:

Neetha answered on Jun 01 2022
100 Votes
PART A: Linear function Review
1.
a) Average rate = 10/4 = 2.5 inches / hour
b) Average rate = 16 – 12 / 3 = 4/3 = 1.333 inches / week
c) Average rate = 180-200/6= (-20/6) = 3.333 pounds/month
d)
At age 10 -> 130 cm
At age 16 -> 175 cm
Average rate = 175 – 130 (16 – 10) = 45/6= 7.5 cm/year
2.
a) per week deposit 10$/week
let x = #of weeks
y = deposited amount in dollars
sketch the initial values
x = 0 , y = 50$
x = 1, y = 60$
x = 2, y = 70$
x = 3, y = 90$
x = 4, y = 90$
slope of the line = 10$/week (already given)
y = mx + c
y = 10$/week * x + c
solve for c for the initial value x = 0, y = 50$
on solving we get 50$
the equation of the line is
y = 10*x + 50
b) m = 1.5 inches / month
c = 10 inches (starting value at month zero)
equation of the line
y = 1.5x + 10
sketch of the initial points given below
x = 0 , y = 10
x = 1, y = 11.5
x = 2, y = 12.5
c) m = 4 pounds / hour
c = 60 punds
equation of the line
y = 4x + 60
sketch of the values given below
x = 0, y = 60
x = 1, y = 4 * 1 + 60 = 64
x = 2, y = 4 * 2 + 60 = 68
x = 3, y = 4 * 3 + 60 = 72
x = 4, y = 4 *4 + 60 = 76
3.
Given :
initial value = 45 gallons
six minutes later
final value = 36 gallons
gallons/minute = 36 – 45/6 = -1.5 gallons/minute
a) y = -1.5x + 45
x = #no of minutes
y = gallons
m = -1.5 gallons/minute
b) the slope is downward and the interceot gives the initial value of the system
c) at x = 20 minutes
y = -1.5 * 20 + 45
= -15/10 * 20 + 45
= -30 + 45
= 15 gallons
at y = 0 , x = ?
using the line equations solve for x
0 = -1.5*x + 45
45/1.5 = x
x = 450/15 = 30 minutes
4.
x = 30 min, y = 32 gallons
x = 50 min, y = 40 gallons
a) m = 40 – 32/ 50 -30 = 8/20 gallons/min
y = (8/20) * x + c
x = 30 , y = 32
solve for c from the above equation
32 = (8/20) * 30 + c
32 – 12 = c
c = 20
y = (8/20) * x + 20
sketch of the graph
b) slope is positive so y is increasing as time increases
and the y- intercpet gives us the inital value that the...
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