Main memory of the basic computer has been shown in the figure below, each instruction and memory variables are represented with the respective physical address (in red and bold font) of each...

Main memory of the basic computer has been shown in the figure below, each instruction and memory variables are represented with the respective physical address (in red and bold font) of each location. PC has value of 1028h and addressing mode is direct.

Main Memory
Address	Content
1028h	LDA 2011h;
1029h	BUN 102Bh;
102Ah	ADD 2012h;
102Bh	AND 2012h;
:	:
2011h	0;
2012h	1;

You are required answer following questions.

• How these instructions will be executed according to instruction execution cycle with respect to the timing signals (T0, T1, T2..)? (10)


• What will be the value of these registers (PC, AR, DR, IR and AC) with respect to timing signals during the execution of each instruction? (10)


• What will the final outcome of the after the execution of instruction at physical address 102Bh? (5)

Extracted text: Memory - reference instruction AND ADD LDA STA DT. DR - M [MAR] D,T. D;T. DR -MLAR) M(AR) + AC SC-0 DR MIAR] DT, D,T, D;T, AC + AC A DR AC - AC + DR E-Ca SC -0 AC + DR sC -0 SC-0 BUN BSA ISZ DJ. DJ. DR -M (AR] DT. PC+ AR M LAR] – PC SC-0 AR AR +1 D,T D,T, DR - DR + 1 PC+ AR SC-O DJ. M(AR) + DR If (DR = 0) then (PC+ PC + 1) SC-0