lust be related in some way to at least one other member of the sample (as in a sibling, friend, or coworker). O The standard deviation of the scores on the anxiety inventory is the samne for those...

8lust be related in some way to at least one other member of the sample (as in a sibling, friend, or<br>coworker).<br>O The standard deviation of the scores on the anxiety inventory is the samne for those who take the anti-anxiety drug and those who don't.<br>Members of the sample are selected randomly.<br>Use the Distributions tool to find the critical region for a = 0.05.<br>Standard Normal Distribution<br>Mean = 0.0<br>Standard Deviation = 1.0<br>-5000<br>2500<br>2500<br>-4<br>-3<br>-2<br>-1<br>-0.674<br>0.674<br>The critical z-scores (the values for z-scores that separate the tails from the main body of the distribution, forming the critical regions) are<br>Calculate the z statistic, and use the Distributions tool to evaluate the null hypothesis. The z statistic is<br>V. The z statistic<br>lie<br>in the critical region for a two-tailed hypothesis test. Therefore, the null hypothesis is<br>

Extracted text: lust be related in some way to at least one other member of the sample (as in a sibling, friend, or coworker). O The standard deviation of the scores on the anxiety inventory is the samne for those who take the anti-anxiety drug and those who don't. Members of the sample are selected randomly. Use the Distributions tool to find the critical region for a = 0.05. Standard Normal Distribution Mean = 0.0 Standard Deviation = 1.0 -5000 2500 2500 -4 -3 -2 -1 -0.674 0.674 The critical z-scores (the values for z-scores that separate the tails from the main body of the distribution, forming the critical regions) are Calculate the z statistic, and use the Distributions tool to evaluate the null hypothesis. The z statistic is V. The z statistic lie in the critical region for a two-tailed hypothesis test. Therefore, the null hypothesis is
Avoid High-Tech Timme<br>Courses<br>A graduate student is performing a study on a new anti-anxiety drug. The drug is supposed to reduce anxiety, but the graduate student realizes that it<br>may do nothing or even increase anxiety, so he decides to formulate nondirectional hypotheses and conduct a two-tailed test. He knows that the<br>O Catalog and Study Tools<br>average score for all anxious people is uo = 25, with a standard deviation of o = 6. If he designates the mean for the population of anxious people<br>who take the anti-anxiety drug as Panti-anxiety drug, he can identify the null and alternative hypotheses as:<br>E Rental Options<br>- College Success Tips<br>Cher<br>Ho: Panti-anxiety drug = Po<br>H1: Panti-anxiety drug + Ho<br>Career Success Tips<br>RECOMMENDED FOR YOU<br>The sample of 36 anxious people who tried out the new anti-anxiety drug scored an average of 23.3.<br>Since the graduate student knows the standard deviation of the scores on the anxiety inventory for the population of people who are anxious, he<br>Wasting<br>intends to use a hypothesis test that uses the z-score of the sample mean as the test statistic (also known as the z test). First, he wants to make sure<br>all the required assumptions are satisfied. Which of the following conditions is not a required assumption for the z test?<br>Wasters<br>O The scores on the anxiety inventory follow a normal distribution or the sample size is large (at least 30).<br>O Each observation is independent of every other observation.<br>e Help<br>O Each member of the sample must be related in some way to at least one other member of the sample (as in a sibling, friend, or<br>Q Give Feedback<br>coworker).<br>O The standard deviation of the scores on the anxiety inventory is the same for those who take the anti-anxiety drug and those who don't.<br>O Members of the sample are selected randomly.<br>Use the Distributions tool to find the critical region for a = 0.05<br>yer<br>Standard Normal Distribution<br>Mean 00<br>Standard Deviation 1.0<br>5000<br>.2500<br>2500<br>-4<br>-3<br>-2<br>-1<br>3<br>4<br>-0.674<br>0.674<br>

Extracted text: Avoid High-Tech Timme Courses A graduate student is performing a study on a new anti-anxiety drug. The drug is supposed to reduce anxiety, but the graduate student realizes that it may do nothing or even increase anxiety, so he decides to formulate nondirectional hypotheses and conduct a two-tailed test. He knows that the O Catalog and Study Tools average score for all anxious people is uo = 25, with a standard deviation of o = 6. If he designates the mean for the population of anxious people who take the anti-anxiety drug as Panti-anxiety drug, he can identify the null and alternative hypotheses as: E Rental Options - College Success Tips Cher Ho: Panti-anxiety drug = Po H1: Panti-anxiety drug + Ho Career Success Tips RECOMMENDED FOR YOU The sample of 36 anxious people who tried out the new anti-anxiety drug scored an average of 23.3. Since the graduate student knows the standard deviation of the scores on the anxiety inventory for the population of people who are anxious, he Wasting intends to use a hypothesis test that uses the z-score of the sample mean as the test statistic (also known as the z test). First, he wants to make sure all the required assumptions are satisfied. Which of the following conditions is not a required assumption for the z test? Wasters O The scores on the anxiety inventory follow a normal distribution or the sample size is large (at least 30). O Each observation is independent of every other observation. e Help O Each member of the sample must be related in some way to at least one other member of the sample (as in a sibling, friend, or Q Give Feedback coworker). O The standard deviation of the scores on the anxiety inventory is the same for those who take the anti-anxiety drug and those who don't. O Members of the sample are selected randomly. Use the Distributions tool to find the critical region for a = 0.05 yer Standard Normal Distribution Mean 00 Standard Deviation 1.0 5000 .2500 2500 -4 -3 -2 -1 3 4 -0.674 0.674
Jun 11, 2022
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