Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the...

Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be​ concluded?

Right arm Left Arm

145 184

138 174

117 192

138 155

130 154

In this​ example,μd is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis​ test?

A.H0​:μd≠0  H1​:μd=0

B.H0​:μd≠0  H1​:μd>0

C.H0​:μd=0  H1​:μd≠0

D.H0​:μd=0  H1​:μd<>

Identify the test statistic.

t=

​(Round to two decimal places as​ needed.)

Identify the​ P-value.

​P-value=

​(Round to three decimal places as​ needed.)

What is the conclusion based on the hypothesis​ test?

Since the​ P-value isless/greaterthan the significance​ level,rejectfail to reject the null hypothesis. Thereis/is not sufficient evidence to support the claim of a difference in measurements between the two arms.