Liquid food is heated in a tubular heat exchanger. The inner pipe wall temperature is 110 ° C. The internal diameter of the pipe is 25 mm. The product flows at 0.5 kg / s If the initial temperature of...

Liquid food is heated in a tubular heat exchanger.  The inner pipe wall temperature is 110 ° C.  The internal diameter of the pipe is 25 mm.  The product flows at 0.5 kg / s If the initial temperature of the product is 7 ° C, calculate the convective heat transfer coefficient.  The thermal properties of the product are as follows.  specific heat = 3.7 kJ / (kg ° C), thermal conductivity = 0.6 W / (m  ° C), product viscosity = 500 x 10 Pa s, density = 1000 kg / m !! product viscosity at 110 ° C = 410  x 106 Pa s

1. Find Reynold's number =


2. Find the Pranti number =


3. Find the Nuselt number =


4. Convection coefficient = W/m° C