(L’Hopital's Rule). Suppose I is an open interval containing a, and f, g : I → R are differentiable on I, except possibly at a. Then, if lim f(x) = 0 and lim g(x) = 0, or if lim f(x) to and lim g(x) =...


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(L’Hopital's Rule). Suppose I is an open interval containing a, and f, g : I → R<br>are differentiable on I, except possibly at a. Then, if<br>lim f(x) = 0 and<br>lim g(x) = 0,<br>or if<br>lim f(x)<br>to and<br>lim g(x) = ±o,<br>then<br>f(x)<br>f'(x)<br>lim<br>lim<br>g(x)<br>x→a g'(x)'<br>f'(x)<br>provided the limit lim<br>exists.<br>g'(x)<br>

Extracted text: (L’Hopital's Rule). Suppose I is an open interval containing a, and f, g : I → R are differentiable on I, except possibly at a. Then, if lim f(x) = 0 and lim g(x) = 0, or if lim f(x) to and lim g(x) = ±o, then f(x) f'(x) lim lim g(x) x→a g'(x)' f'(x) provided the limit lim exists. g'(x)
Prove the

Extracted text: Prove the "o/0" case of l'Hopital's rule. That is, prove that if f : I → R and g : I → R are differentiable functions satisfying lim f(x) = = lim g(x) for a E I, then f' (x) gʻ(x) f(x) x→a g(x) lim = L implies lim L.

Jun 05, 2022
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