Let {xn} be a sequence of real numbers. Let yn be the average of the first n-terms: X1 + x2 + + Xn Yn n Prove that if {xn} converges to xo, then {yn} also converges to xo. (Hint: using the definition...


Let {xn} be a sequence of real numbers. Let yn be the average of the first<br>n-terms:<br>X1 + x2 +<br>+ Xn<br>Yn<br>n<br>Prove that if {xn} converges to xo, then {yn} also converges to xo. (Hint: using<br>the definition of convergence, choose a large threshold N after which |Xn – x∞| is as small as<br>we want, then choose n large enough such that the |x; – x|/n is very small for 1 < i < N.)<br>Consider a numerical series 1 an. Denote by sn =<br>of the first n-partial sums be<br>Lk=1 ak the partial sums. Let the average<br>S1 + 82 +<br>+ Sn<br>On =<br>As a direct corollary of part a), the convergence of {Sn} implies that of {on}. In the following<br>problems, we explore when the convergence of {on} implies that of {sn}.<br>If {on} converges to o, and ak = o() as k → 0 (ak is “small Oh

Extracted text: Let {xn} be a sequence of real numbers. Let yn be the average of the first n-terms: X1 + x2 + + Xn Yn n Prove that if {xn} converges to xo, then {yn} also converges to xo. (Hint: using the definition of convergence, choose a large threshold N after which |Xn – x∞| is as small as we want, then choose n large enough such that the |x; – x|/n is very small for 1 < i="">< n.)="" consider="" a="" numerical="" series="" 1="" an.="" denote="" by="" sn="of" the="" first="" n-partial="" sums="" be="" lk="1" ak="" the="" partial="" sums.="" let="" the="" average="" s1="" +="" 82="" +="" +="" sn="" on="As" a="" direct="" corollary="" of="" part="" a),="" the="" convergence="" of="" {sn}="" implies="" that="" of="" {on}.="" in="" the="" following="" problems,="" we="" explore="" when="" the="" convergence="" of="" {on}="" implies="" that="" of="" {sn}.="" if="" {on}="" converges="" to="" o,="" and="" ak="o()" as="" k="" →="" 0="" (ak="" is="" “small="" oh"="" of="" ),="" prove="" that="" {sn}="" also="" converges="" to="" o.="" (hint:="" express="" the="" difference="" sn-on="" using="" {kak="" :="" k="1," ·="" ·.="" ,n}.)="" as="" k="" →="" o="" (ak="" is="" “big="" oh"="" of="" if="" {on}="" converges="" to="" oo,="" and="" ak=")," prove="" that="" {sn}="" also="" converges="" to="" ooo="">

Jun 04, 2022
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