Let X u...,Xn be independently and identically distributed normal random variables with E(X]) = |xt, var(AT/) = 1 for i = 1 Let 8 2 = |x-. Show that the pdf of U = 2f=1 X] is given by f v(i) = 2f=i...



Let X u...,Xn be independently and identically distributed normal random variables with E(X]) = |xt, var(AT/) = 1 for i = 1 Let 8 2 =


|x-. Show that the pdf of U = 2f=1 X] is given by f v(i) =


2f=i Pv(i)f(x2n+2i), where p v(i) is the pdf of a Poisson random variable


with parameter \ S2, f(xl+n) is the pdf of a central chi-square with


n + 2i degrees of freedom and V is independent of xl+v- {Note: This


is also known as the pdf of a noncentral chi-square random variable


with n degrees of freedom and noncentrality parameter 8 2.)



May 26, 2022
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