Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the...


Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the minimum has a Weibull distribution with parameters a = 2 and B = 1.5.<br>(a) What is the cdf of X?<br>x< 5.5<br>F(x) = {<br>x2 5.5<br>(b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 5.5) and V(X - 5.5).] (Round your answers to three decimal places.)<br>E(X) =<br>V(X) =|<br>10-1 weeks<br>(10-1 weeks)?<br>(c) Compute P(X > 7). (Round your answer to four decimal places.)<br>(d) Compute P(7 SXS 8.5). (Round your answer to four decimal places.)<br>

Extracted text: Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the minimum has a Weibull distribution with parameters a = 2 and B = 1.5. (a) What is the cdf of X? x< 5.5="" f(x)="{" x2="" 5.5="" (b)="" what="" are="" the="" expected="" return="" time="" and="" variance="" of="" return="" time?="" [hint:="" first="" obtain="" e(x="" -="" 5.5)="" and="" v(x="" -="" 5.5).]="" (round="" your="" answers="" to="" three="" decimal="" places.)="" e(x)="V(X)" =|="" 10-1="" weeks="" (10-1="" weeks)?="" (c)="" compute="" p(x=""> 7). (Round your answer to four decimal places.) (d) Compute P(7 SXS 8.5). (Round your answer to four decimal places.)

Jun 09, 2022
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