Let X be continuous with pdf f(x)=e* if 0


Let X be continuous with pdf f(x)=e* if 0 < x < ∞, and zero otherwise: .<br>Use Chebychev's inequality to obtain a lower bound on P(-1.5 <x< 3.5).<br>b. Compare this bound to the exact probability.<br>c. Use Markov's inequality to find a bound on P(x 2 3).<br>

Extracted text: Let X be continuous with pdf f(x)=e* if 0 < x="">< ∞,="" and="" zero="" otherwise:="" .="" use="" chebychev's="" inequality="" to="" obtain="" a="" lower="" bound="" on="" p(-1.5=""><>< 3.5).="" b.="" compare="" this="" bound="" to="" the="" exact="" probability.="" c.="" use="" markov's="" inequality="" to="" find="" a="" bound="" on="" p(x="" 2="">

Jun 04, 2022
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