Let X and Y be random variables such that, for some a > 0, P(X = m, Y = n) = a 2m+n (0.54)m+n %3D m!n! for m = 0,1, 2, 3, ... and n = 0, 1, 2, 3, .... Find a, giving your answer in four decimal...

Let X and Y be random variables such that, for some a > 0,<br>P(X = m, Y = n) = a 2m+n<br>(0.54)m+n<br>%3D<br>m!n!<br>for m = 0,1, 2, 3, ... and n = 0, 1, 2, 3, ....<br>Find a, giving your answer in four decimal places.<br>Answer:<br>

Extracted text: Let X and Y be random variables such that, for some a > 0, P(X = m, Y = n) = a 2m+n (0.54)m+n %3D m!n! for m = 0,1, 2, 3, ... and n = 0, 1, 2, 3, .... Find a, giving your answer in four decimal places. Answer:

Jun 11, 2022

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Let X and Y be random variables such that, for some a > 0, P(X = m, Y = n) = a 2m+n (0.54)m+n %3D m!n! for m = 0,1, 2, 3, ... and n = 0, 1, 2, 3, .... Find a, giving your answer in four decimal...

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