(a) What is the level of significance?
State the null and alternate hypotheses.
Ho
: σ2
= 5.1;
H1
: σ2
> 5.1Ho
: σ2
<>
H1
: σ2
= 5.1
Ho
: σ2
= 5.1;
H1
: σ2
<>Ho
: σ2
= 5.1;
H1
: σ2
≠ 5.1
(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the original distribution?
We assume a uniform population distribution.We assume a normal population distribution. We assume a binomial population distribution.We assume a exponential population distribution.
(c) Find or estimate the
P-value of the sample test statistic.
P-value > 0.1000.050
P-value < 0.100 ="" 0.025="">
P-value < 0.0500.010="">
P-value < 0.0250.005="">
P-value <>P-value <>
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?
Since the
P-value > α, we fail to reject the null hypothesis.Since the
P-value > α, we reject the null hypothesis. Since the
P-value ≤ α, we reject the null hypothesis.Since the
P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
At the 5% level of significance, there is insufficient evidence to conclude that the variance of age at first marriage is less than 5.1.At the 5% level of significance, there is sufficient evidence to conclude that the that the variance of age at first marriage is less than 5.1.
(f) Find the requested confidence interval for the population variance. (Round your answers to two decimal places.)
Interpret the results in the context of the application.
We are 90% confident that σ2
lies within this interval.We are 90% confident that σ2
lies above this interval. We are 90% confident that σ2
lies outside this interval.We are 90% confident that σ2
lies below this interval.