Let X = {a, b, c, d}, and consider B1 = { {a}, {b,d}, {c,d}} and B2 = {{a,b}, {c,d}, {b,d}}. Then * B1 is a basis for a topology on X but B2 is not B2 is a basis for a topology on X but B1 is not B1...

Let X = {a, b, c, d}, and consider B1 = {<br>{a}, {b,d}, {c,d}} and B2 = {{a,b}, {c,d},<br>{b,d}}. Then *<br>B1 is a basis for a topology on X but<br>B2 is not<br>B2 is a basis for a topology on X but<br>B1 is not<br>B1 and B2 are not bases for a<br>topology on X<br>B1 and B2 are both bases for a<br>topology on X<br>

Extracted text: Let X = {a, b, c, d}, and consider B1 = { {a}, {b,d}, {c,d}} and B2 = {{a,b}, {c,d}, {b,d}}. Then * B1 is a basis for a topology on X but B2 is not B2 is a basis for a topology on X but B1 is not B1 and B2 are not bases for a topology on X B1 and B2 are both bases for a topology on X

Jun 04, 2022

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Let X = {a, b, c, d}, and consider B1 = { {a}, {b,d}, {c,d}} and B2 = {{a,b}, {c,d}, {b,d}}. Then * B1 is a basis for a topology on X but B2 is not B2 is a basis for a topology on X but B1 is not B1...

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