Let S be the set of integers and H be the set of all odd integers. Then the subset H of S is closed under the usual multiplication. True False Let a + b = ab – 2. Then 2 is the identity element of Z...


Answer if TRUE or FALSE


Let S be the set of integers and H be the set of all odd integers. Then the subset H of S is<br>closed under the usual multiplication.<br>True<br>False<br>Let a + b = ab – 2. Then 2 is the identity element of Z under *.<br>True<br>False<br>Let a + b = ab – 2. Then the inverse element of a in Z does not exist.<br>True<br>False<br>

Extracted text: Let S be the set of integers and H be the set of all odd integers. Then the subset H of S is closed under the usual multiplication. True False Let a + b = ab – 2. Then 2 is the identity element of Z under *. True False Let a + b = ab – 2. Then the inverse element of a in Z does not exist. True False

Jun 05, 2022
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