Let S and T be subsets of. Find a counterexample for each of the following.
(a) If P is the set of all isolated points of S, then P is a closed set.
(b) Every open set contains at least two points.
(c) If S is closed, then cl (int S ) = S.
(d) If S is open, then int (cl S ) = S.
(e) bd (cl S ) = bd S
(f ) bd (bd S ) = bd S
(g) bd (S ∪ T ) = (bd S ) ∪ (bd T )
(h) bd (S ∩ T ) = (bd S ) ∩ (bd T )
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