Let R be the triangular region of the plane with vertices (0, 0), (2, 1), and (1, 2). Consider the double integral I = I| (3y – a) dA. Set x = 2u + v and y = u+ 2v. (a) In the (u, v)-plane, the image...


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Let R be the triangular region of the plane with vertices (0, 0), (2, 1), and (1, 2).<br>Consider the double integral<br>I =<br>I| (3y – a) dA.<br>Set x = 2u + v and y = u+ 2v.<br>(a) In the (u, v)-plane, the image of R becomes the triangle with vertices<br>(1) {(0,0), (0, 1) , (1,1)}<br>(2) {(0,0), (1,0) , (1,1)}<br>(3) {(0,0), (1,0) , (0,1)}<br>(4) {(0,1), (1,0) , (1, 1)}<br>14of24<br>(b) The Jacobian of the transformation taking (x, y) to (u, v) is<br>(1) – 1/3<br>(2) - 3<br>(3) 1/3<br>(4) 3<br>(c) Evaluate the integral I by changing coordinates to (u, v).<br>Your answer to (a):<br>Your answer to (b):<br>Your answer to (c):<br>

Extracted text: Let R be the triangular region of the plane with vertices (0, 0), (2, 1), and (1, 2). Consider the double integral I = I| (3y – a) dA. Set x = 2u + v and y = u+ 2v. (a) In the (u, v)-plane, the image of R becomes the triangle with vertices (1) {(0,0), (0, 1) , (1,1)} (2) {(0,0), (1,0) , (1,1)} (3) {(0,0), (1,0) , (0,1)} (4) {(0,1), (1,0) , (1, 1)} 14of24 (b) The Jacobian of the transformation taking (x, y) to (u, v) is (1) – 1/3 (2) - 3 (3) 1/3 (4) 3 (c) Evaluate the integral I by changing coordinates to (u, v). Your answer to (a): Your answer to (b): Your answer to (c):

Jun 04, 2022
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