Let k e Zt. Let A be a set such that |A| = k + 1, and let a € A (i.e., a is a fixed but unspecified element of A). Define X:= {X | X C A and a ¢ X} Y := {Y | Y C A and a E Y}

Let k e Zt. Let A be a set such that |A| = k + 1, and let a € A (i.e., a is a fixed but<br>unspecified element of A). Define<br>X:= {X | X C A and a ¢ X}<br>Y := {Y | Y C A and a E Y}<br>

Extracted text: Let k e Zt. Let A be a set such that |A| = k + 1, and let a € A (i.e., a is a fixed but unspecified element of A). Define X:= {X | X C A and a ¢ X} Y := {Y | Y C A and a E Y}

4. Show that the function f : X → Y defined by<br>f(X) = XU {a} VX € X<br>is a bijection.<br>

Extracted text: 4. Show that the function f : X → Y defined by f(X) = XU {a} VX € X is a bijection.

Jun 05, 2022

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Let k e Zt. Let A be a set such that |A| = k + 1, and let a € A (i.e., a is a fixed but unspecified element of A). Define X:= {X | X C A and a ¢ X} Y := {Y | Y C A and a E Y}

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