Let gn be the 1-NN classification rule. Prove that
lim n→∞ P{gn(X) = Y } = 1 − M j=1 E{m(j) (X) 2 }
for all distributions of (X, Y ), where m(j) (X) = P{Y = j|X} (Cover and Hart (1967), Stone (1977)).
Hint:
Step (a). Show that
P{gn(X) = Y } = 1 − M j=1 P{Y = j, gn(X) = j}
= 1 − M j=1 E{m(j) (X)m(j) (X(1,n)(X))}.
Step (b). Problem 6.3 implies that
lim n→∞ E{(m(j) (X) − m(j) (X(1,n)(X)))2 } = 0.
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