Let gn be the 1-NN classification rule. Prove that                         lim n→∞ P{gn(X) = Y } = 1 − M j=1 E{m(j) (X) 2 } for all distributions of (X, Y ), where m(j) (X) = P{Y = j|X} (Cover and...


Let gn be the 1-NN classification rule. Prove that


                        lim n→∞ P{gn(X) = Y } = 1 − M j=1 E{m(j) (X) 2 }


for all distributions of (X, Y ), where m(j) (X) = P{Y = j|X} (Cover and Hart (1967), Stone (1977)).


Hint:


Step (a). Show that


                                P{gn(X) = Y } = 1 − M j=1 P{Y = j, gn(X) = j}


                               = 1 − M j=1 E{m(j) (X)m(j) (X(1,n)(X))}.


Step (b). Problem 6.3 implies that


                               lim n→∞ E{(m(j) (X) − m(j) (X(1,n)(X)))2 } = 0.



May 23, 2022
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