Let (fn), be a sequence of functions fa : [0,1] → R defined by fa(x) = fo , if zs! Then 1. f, converges to 0 pointwisely on [0, 1] since f, converges to 0 pointwisely. 2. fn converges to 0 uniformly...

Extracted text: Let (fn), be a sequence of functions fa : [0,1] → R defined by fa(x) = fo , if zs! Then 1. f, converges to 0 pointwisely on [0, 1] since f, converges to 0 pointwisely. 2. fn converges to 0 uniformly on [0, 1] and thus f fa(x)dx converges to f f(z)dr. 3. fn converges to f = 0 pointwisely on [0, 1] but not uniformly. 4. fn doesn't converge pointwisely to 0 on [0, 1]. 1 O 2 Оз 3 O 4