Let f (x) = (x+1)= Using the centered 3-point formula for 1st derivatives: f'(0) × –0.502509 using h = 0.1 f'(0) 2 -0.500626 using h = 0.05 Applying Richardson's extrapolation on the above values, we...

Let f (x) =<br>(x+1)=<br>Using the centered 3-point formula for 1st derivatives:<br>f'(0) × –0.502509 using h = 0.1<br>f'(0) 2 -0.500626 using h = 0.05<br>Applying Richardson's extrapolation on the above values, we get a better approximation of<br>f'(0) which is:<br>0.234256<br>O -1.99985<br>0.249999<br>-0.499998<br>

Extracted text: Let f (x) = (x+1)= Using the centered 3-point formula for 1st derivatives: f'(0) × –0.502509 using h = 0.1 f'(0) 2 -0.500626 using h = 0.05 Applying Richardson's extrapolation on the above values, we get a better approximation of f'(0) which is: 0.234256 O -1.99985 0.249999 -0.499998

Jun 04, 2022

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Let f (x) = (x+1)= Using the centered 3-point formula for 1st derivatives: f'(0) × –0.502509 using h = 0.1 f'(0) 2 -0.500626 using h = 0.05 Applying Richardson's extrapolation on the above values, we...

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